Electrical Engineering - Magnetism and Electromagnetism - Discussion
Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 6)
6.
What is the reluctance of a material that has a length of 0.07 m, a cross-sectional area of 0.014 m2, and a permeability of 4,500 
Wb/At × m?
Wb/At × m?Discussion:
17 comments Page 1 of 2.
Gabrielle said:
2 years ago
Reluctance = length/Uo * Ur * Area.
Given:
Permeability (U) = 4500u Wb/Atxm.
Find Ur (relative permeability):
Ur=Permeability (U) /Free Space Permeability (Uo).
Ur =4500×10^-6 / 4pix10^-7 = 3580.98.
Reluctance = 0.07 / (4pix10^-7) (3580.98) (0.014).
Reluctance = 1111.11 At/Wb.
Given:
Permeability (U) = 4500u Wb/Atxm.
Find Ur (relative permeability):
Ur=Permeability (U) /Free Space Permeability (Uo).
Ur =4500×10^-6 / 4pix10^-7 = 3580.98.
Reluctance = 0.07 / (4pix10^-7) (3580.98) (0.014).
Reluctance = 1111.11 At/Wb.
(4)
Swetha said:
7 years ago
Key point is;
Resistivity is inversely proportional to permeability.
Resistance = length/ua.
Resistivity is inversely proportional to permeability.
Resistance = length/ua.
(2)
Akshaya said:
8 years ago
S=l/ (uoura).
uo=means permittivity ur=permeability.
uo=means permittivity ur=permeability.
(2)
Dan said:
1 decade ago
Formula for this one?
(1)
Rutu said:
5 years ago
Well said @Swetha.
(1)
Vishnu said:
8 years ago
R = pL/A, S = L/uA.
p=Resistivity u = Permeability.
So,
S = .07/(0.014*4500* 10^-6) = 1111 At/Wb.
p=Resistivity u = Permeability.
So,
S = .07/(0.014*4500* 10^-6) = 1111 At/Wb.
(1)
Puspendra singh said:
9 years ago
Can anyone explain it by a easy calculation? please.
(1)
Robin Bhowmick said:
9 years ago
Try to understand using your common sense and logic rather than memorising the formula.
Engineering is an art, it cannot be mastered only memorising the study.
Engineering is an art, it cannot be mastered only memorising the study.
Razin said:
9 years ago
The value of permeability is give not relative permeability.
Kannan said:
1 decade ago
It's nice.
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