Electrical Engineering - Magnetism and Electromagnetism - Discussion
Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 6)
6.
What is the reluctance of a material that has a length of 0.07 m, a cross-sectional area of 0.014 m2, and a permeability of 4,500
Wb/At × m?

Discussion:
17 comments Page 1 of 2.
Gabrielle said:
2 years ago
Reluctance = length/Uo * Ur * Area.
Given:
Permeability (U) = 4500u Wb/Atxm.
Find Ur (relative permeability):
Ur=Permeability (U) /Free Space Permeability (Uo).
Ur =4500×10^-6 / 4pix10^-7 = 3580.98.
Reluctance = 0.07 / (4pix10^-7) (3580.98) (0.014).
Reluctance = 1111.11 At/Wb.
Given:
Permeability (U) = 4500u Wb/Atxm.
Find Ur (relative permeability):
Ur=Permeability (U) /Free Space Permeability (Uo).
Ur =4500×10^-6 / 4pix10^-7 = 3580.98.
Reluctance = 0.07 / (4pix10^-7) (3580.98) (0.014).
Reluctance = 1111.11 At/Wb.
(4)
Rutu said:
5 years ago
Well said @Swetha.
(1)
Swetha said:
7 years ago
Key point is;
Resistivity is inversely proportional to permeability.
Resistance = length/ua.
Resistivity is inversely proportional to permeability.
Resistance = length/ua.
(2)
Akshaya said:
8 years ago
S=l/ (uoura).
uo=means permittivity ur=permeability.
uo=means permittivity ur=permeability.
(2)
Naresh said:
8 years ago
1111 At/Wb.
Vishnu said:
8 years ago
R = pL/A, S = L/uA.
p=Resistivity u = Permeability.
So,
S = .07/(0.014*4500* 10^-6) = 1111 At/Wb.
p=Resistivity u = Permeability.
So,
S = .07/(0.014*4500* 10^-6) = 1111 At/Wb.
(1)
Shir Ahmad said:
8 years ago
Rf= Lavg /permeability* area.
So that after the analysis it find 1111.
So that after the analysis it find 1111.
Puspendra singh said:
9 years ago
Can anyone explain it by a easy calculation? please.
(1)
Razin said:
9 years ago
The value of permeability is give not relative permeability.
Robin Bhowmick said:
9 years ago
Try to understand using your common sense and logic rather than memorising the formula.
Engineering is an art, it cannot be mastered only memorising the study.
Engineering is an art, it cannot be mastered only memorising the study.
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