Electrical Engineering - Inductors - Discussion

Discussion Forum : Inductors - General Questions (Q.No. 5)
5.
The voltage across a coil when di/dt = 20 mA/s and L = 8 H is
16 mV
160 mV
1.6 mV
2.5 mV
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 1 of 2.

Deepika said:   1 decade ago
Given inductance = 8*10^-6henry. { Henry symbol is H }

and also di/dt means given change of current 20*10^-3amperes.

Current is measured in amperes. Inductance is measured in henry.

To find the voltage L *di/dt = 8*10^-6*20*10^-3/10^-6

= 160*10^-3

= 160mv

voltage is measured in volts.

Krushnapada said:   8 years ago
We all know that the formula of the inductor for finding voltage. Is Ldi/it.
So data given,
L = 8*10^-6 H.

di/DT=20*10^-3/10^-6.
So according to formula.
V = 8 * 10^-6 * 20 * 10^-3/10^-6.
= 160*10^-3v.
(2)

Pramod said:   10 years ago
Given data,

Rate of change of current = 20 mA/micro sec.

Inductor = 8 microhenry.

From the formula:

Voltage across inductor (V) = L * Rate of change of current,

So, V = 8*20 = 160 mv.
(1)

Deepika said:   1 decade ago
Given change of current di/dt = 20*10^-3amperes./10^-6 s

Inductance = 8*10^-6henry.

To find voltage = L*di/dt = 8*10^-6*20*10^-3/10^-6

= 160*10^-3 v.

= 160 milli volts.

Pavan said:   10 years ago
Inductor stores energy in the form of electromagnetic field.

Output Voltage can be varied when current through it will change with time t. So v = L*di/dt.

Engr.talha said:   5 years ago
Why we are dividing it by 10^-6? Please explain about it.
(2)

Stuti said:   10 years ago
V = LDI/DT.

= 8*10^-6*20*10^-3/10^-6.

= 160*10^-3v.

Ram said:   7 years ago
v = Ldi/dt.
= 8 * 20.
= 160V.

Dinesh said:   9 years ago
Helpful solution, Thank you all.

Priyanka said:   7 years ago
V = Ldi/dt,
= 8 * 20.
= 160V.


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