Electrical Engineering - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 5)
5.
The voltage across a coil when di/dt = 20 mA/
s and L = 8 H is
s and L = 8 H isDiscussion:
13 comments Page 1 of 2.
Engr.talha said:
3 years ago
Why we are dividing it by 10^-6? Please explain about it.
Ram said:
5 years ago
v = Ldi/dt.
= 8 * 20.
= 160V.
= 8 * 20.
= 160V.
Priyanka said:
5 years ago
V = Ldi/dt,
= 8 * 20.
= 160V.
= 8 * 20.
= 160V.
Krushnapada said:
6 years ago
We all know that the formula of the inductor for finding voltage. Is Ldi/it.
So data given,
L = 8*10^-6 H.
di/DT=20*10^-3/10^-6.
So according to formula.
V = 8 * 10^-6 * 20 * 10^-3/10^-6.
= 160*10^-3v.
So data given,
L = 8*10^-6 H.
di/DT=20*10^-3/10^-6.
So according to formula.
V = 8 * 10^-6 * 20 * 10^-3/10^-6.
= 160*10^-3v.
Ravi said:
6 years ago
Thank you @Pramod.
Dinesh said:
7 years ago
Helpful solution, Thank you all.
Stuti said:
7 years ago
V = LDI/DT.
= 8*10^-6*20*10^-3/10^-6.
= 160*10^-3v.
= 8*10^-6*20*10^-3/10^-6.
= 160*10^-3v.
Pramod said:
7 years ago
Given data,
Rate of change of current = 20 mA/micro sec.
Inductor = 8 microhenry.
From the formula:
Voltage across inductor (V) = L * Rate of change of current,
So, V = 8*20 = 160 mv.
Rate of change of current = 20 mA/micro sec.
Inductor = 8 microhenry.
From the formula:
Voltage across inductor (V) = L * Rate of change of current,
So, V = 8*20 = 160 mv.
(1)
Pavan said:
8 years ago
Inductor stores energy in the form of electromagnetic field.
Output Voltage can be varied when current through it will change with time t. So v = L*di/dt.
Output Voltage can be varied when current through it will change with time t. So v = L*di/dt.
MAHESH said:
8 years ago
V = LDI/DT.
= 8*20.
= 160.
= 8*20.
= 160.
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