# Electrical Engineering - Inductors - Discussion

Discussion Forum : Inductors - General Questions (Q.No. 5)
5.
The voltage across a coil when di/dt = 20 mA/ s and L = 8 H is
16 mV
160 mV
1.6 mV
2.5 mV
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 1 of 2.

Engr.talha said:   3 years ago

Ram said:   5 years ago
v = Ldi/dt.
= 8 * 20.
= 160V.

Priyanka said:   5 years ago
V = Ldi/dt,
= 8 * 20.
= 160V.

We all know that the formula of the inductor for finding voltage. Is Ldi/it.
So data given,
L = 8*10^-6 H.

di/DT=20*10^-3/10^-6.
So according to formula.
V = 8 * 10^-6 * 20 * 10^-3/10^-6.
= 160*10^-3v.

Ravi said:   6 years ago
Thank you @Pramod.

Dinesh said:   7 years ago

Stuti said:   7 years ago
V = LDI/DT.

= 8*10^-6*20*10^-3/10^-6.

= 160*10^-3v.

Pramod said:   7 years ago
Given data,

Rate of change of current = 20 mA/micro sec.

Inductor = 8 microhenry.

From the formula:

Voltage across inductor (V) = L * Rate of change of current,

So, V = 8*20 = 160 mv.
(1)

Pavan said:   8 years ago
Inductor stores energy in the form of electromagnetic field.

Output Voltage can be varied when current through it will change with time t. So v = L*di/dt.

MAHESH said:   8 years ago
V = LDI/DT.
= 8*20.
= 160.