### Discussion :: Inductors - General Questions (Q.No.6)

Santosh Kumar said: (Mar 4, 2011) | |

When frequency decrease indultance also decrease and so current increase. |

Abdul Rauff said: (Dec 14, 2011) | |

Xl = jwL = j*2*pi*f*L so when f decreases ,Xl decreases and current increase |

Md Jamshed Nausherwan said: (Mar 27, 2012) | |

I=v/Xl, so XL=6. 8fl, thats why frequency reducing current will be increased. |

Sumeet Kumar said: (Apr 28, 2012) | |

In pure inductor I=V/XL,whereXL is inductive reactance XL=2pifl As f decreases XL also decreases thus I(CURRENT) increases |

Vijay Krishna said: (Dec 21, 2012) | |

We know that as inductance decreases then current increases. Also Since Xl=2*3014*l*f. As frequency decreases inductance also decreases. |

Muhammad Yaqub said: (Apr 5, 2013) | |

XL and current are inversely proportional, and XL=2pi fL so when frequency decreases current will increases because they are inversely proportional. |

Upendra said: (Dec 2, 2014) | |

Sinusoidal signal means A.C source so impudence present in circuit so inductive reactance is inversely proportional to voltage and directly proportional to current then current increases. |

Taniya said: (Feb 11, 2015) | |

We know that, inductance opposes the flow of current. Therefore if inductance decreases by decreasing frequency, then current will increase, since the opposition (inductance) has decreased. |

Er.Pankaj Pandey said: (Feb 12, 2015) | |

We know that inductance is a function of frequency which is directly proportional. If f increase then inductance increase. But I is inversely proportional to inductance. So I will increase when f decrease. |

Amit Patel said: (Jun 24, 2015) | |

V=Vmsin2pi.ft. When the frequency is decrease than voltage is also decrease, so current will not be change. |

Dhiraj said: (Jul 24, 2015) | |

When the frequency decreases, means AC is converted to DC, the inductor act as short circuit in DC. That's the reason when frequency reduces current increase. |

Stuti said: (Feb 15, 2016) | |

We know, XL = 2f*3.14l. So if frequency decrease then XL also decease by which opposition of current also decrease and more current flow therefore current increase. |

Rafiq said: (Sep 10, 2016) | |

Current increases because it is inversely proportion to the inductive reactance. |

Raf said: (Sep 10, 2016) | |

@Taniya is right. |

Bhargav said: (Dec 8, 2016) | |

Frequency decreased means time period increases. Hence voltage decreases. Therefore current decreases. |

Albert said: (May 25, 2017) | |

Yes, You are right @Bhargav. |

Kamlesh Yadav said: (Sep 8, 2017) | |

Here, f proportional to V/I. Then f decreases with increases I. |

D Shwetha said: (Sep 8, 2018) | |

@Sumeet. Your explanation is good. I=V/XL, I=V/2πfL, If Frequency decrease, I will increase. |

Shivu said: (Sep 22, 2019) | |

Current will remains the same, because inductor which opposes the change of current. |

Abbas said: (Oct 5, 2020) | |

If xl= 2p then it will increases. |

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