Electrical Engineering - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 6)
6.
A sine wave voltage is applied across an inductor. When the frequency of the voltage is decreased, the current
Discussion:
21 comments Page 1 of 3.
Anand said:
4 years ago
v=L di/dt & XL=2pifL there fore L= XL/2p.
If;
V=XL/2pif * di/dt.
di/dt= V2pif/XL. if frequency decreases, current decreases.
If;
V=XL/2pif * di/dt.
di/dt= V2pif/XL. if frequency decreases, current decreases.
(1)
Abbas said:
5 years ago
If xl= 2p then it will increases.
Shivu said:
6 years ago
Current will remains the same, because inductor which opposes the change of current.
D Shwetha said:
7 years ago
@Sumeet.
Your explanation is good.
I=V/XL,
I=V/2πfL,
If Frequency decrease, I will increase.
Your explanation is good.
I=V/XL,
I=V/2πfL,
If Frequency decrease, I will increase.
(3)
Kamlesh yadav said:
8 years ago
Here, f proportional to V/I.
Then f decreases with increases I.
Then f decreases with increases I.
Albert said:
8 years ago
Yes, You are right @Bhargav.
(1)
Bhargav said:
9 years ago
Frequency decreased means time period increases. Hence voltage decreases. Therefore current decreases.
(1)
Raf said:
9 years ago
@Taniya is right.
Rafiq said:
9 years ago
Current increases because it is inversely proportion to the inductive reactance.
Stuti said:
10 years ago
We know,
XL = 2f*3.14l.
So if frequency decrease then XL also decease by which opposition of current also decrease and more current flow therefore current increase.
XL = 2f*3.14l.
So if frequency decrease then XL also decease by which opposition of current also decrease and more current flow therefore current increase.
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