Electrical Engineering - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 6)
6.
A sine wave voltage is applied across an inductor. When the frequency of the voltage is decreased, the current
Discussion:
21 comments Page 2 of 3.
Dhiraj said:
1 decade ago
When the frequency decreases, means AC is converted to DC, the inductor act as short circuit in DC. That's the reason when frequency reduces current increase.
Amit patel said:
1 decade ago
V=Vmsin2pi.ft.
When the frequency is decrease than voltage is also decrease, so current will not be change.
When the frequency is decrease than voltage is also decrease, so current will not be change.
Er.Pankaj pandey said:
1 decade ago
We know that inductance is a function of frequency which is directly proportional. If f increase then inductance increase. But I is inversely proportional to inductance. So I will increase when f decrease.
Taniya said:
1 decade ago
We know that, inductance opposes the flow of current. Therefore if inductance decreases by decreasing frequency, then current will increase, since the opposition (inductance) has decreased.
Upendra said:
1 decade ago
Sinusoidal signal means A.C source so impudence present in circuit so inductive reactance is inversely proportional to voltage and directly proportional to current then current increases.
Muhammad yaqub said:
1 decade ago
XL and current are inversely proportional, and XL=2pi fL so when frequency decreases current will increases because they are inversely proportional.
Vijay krishna said:
1 decade ago
We know that as inductance decreases then current increases. Also
Since Xl=2*3014*l*f. As frequency decreases inductance also decreases.
Since Xl=2*3014*l*f. As frequency decreases inductance also decreases.
Sumeet kumar said:
1 decade ago
In pure inductor
I=V/XL,whereXL is inductive reactance
XL=2pifl
As f decreases XL also decreases thus I(CURRENT) increases
I=V/XL,whereXL is inductive reactance
XL=2pifl
As f decreases XL also decreases thus I(CURRENT) increases
MD JAMSHED NAUSHERWAN said:
1 decade ago
I=v/Xl, so XL=6. 8fl, thats why frequency reducing current will be increased.
Abdul Rauff said:
1 decade ago
Xl = jwL = j*2*pi*f*L
so when f decreases ,Xl decreases and current increase
so when f decreases ,Xl decreases and current increase
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