Electrical Engineering - Inductors - Discussion

Discussion Forum : Inductors - General Questions (Q.No. 4)
4.
A 5 mH, a 4.3 mH, and a 0.6 mH inductor are connected in parallel. The total inductance is
9.9 mH
greater than 5 mH
9.9 mH or greater than 5 mH
less than 0.6 mH
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
7 comments Page 1 of 1.

SHIVAKUMAR K S said:   1 decade ago
In any parallel combination of resistance or inductance the equivalent resistance or inductance is less than the least value of individual one.

Hence 0.6 is the least value in the combination of inductance in parallel.

ANS : 0.6.
(2)

Satish kumar said:   1 decade ago
Ans:D
if the inductances(resistances) are connected in parallel,the equivalent inductances(resistances) will be less than the smaller individual inductance(resistance) coz... of the formula (1/Leq)=(1/L1)+(1/L2)+......+(1/Ln)

Thirumal said:   1 decade ago
Ans : D
If the inductor are connected in parallel connection , then the formula for Equivalent Inductance is same as that of the Resistance.

i.e. (1/Leq)= (1/L1)+(1/L2)+(1/L3)

So (1/Leq) = (1/5m)+(1/4.3m)+(1/0.6m)
(1/Leq) = 2099.2248

Therefore
Leq = 1/2099.2248 = 0.47 mH
Which is less than 0.6 mH.

Soujanya said:   7 years ago
Thank you @Shivakumar K S.

D Shwetha said:   7 years ago
@Shivakumar.

Your explanation is short & good. Thank you.

Waseem said:   7 years ago
How to solve this? Please tell me.

Haseeb said:   5 years ago
The Equation. L = L2L3 + L1L3 + L1L2/L1L2L3.

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