# Electrical Engineering - Inductors - Discussion

Discussion Forum : Inductors - General Questions (Q.No. 4)

4.

A 5 mH, a 4.3 mH, and a 0.6 mH inductor are connected in parallel. The total inductance is

Discussion:

7 comments Page 1 of 1.
Haseeb said:
3 years ago

The Equation. L = L2L3 + L1L3 + L1L2/L1L2L3.

Waseem said:
5 years ago

How to solve this? Please tell me.

D Shwetha said:
5 years ago

@Shivakumar.

Your explanation is short & good. Thank you.

Your explanation is short & good. Thank you.

Soujanya said:
5 years ago

Thank you @Shivakumar K S.

SHIVAKUMAR K S said:
8 years ago

In any parallel combination of resistance or inductance the equivalent resistance or inductance is less than the least value of individual one.

Hence 0.6 is the least value in the combination of inductance in parallel.

ANS : 0.6.

Hence 0.6 is the least value in the combination of inductance in parallel.

ANS : 0.6.

(1)

Thirumal said:
1 decade ago

Ans : D

If the inductor are connected in parallel connection , then the formula for Equivalent Inductance is same as that of the Resistance.

i.e. (1/Leq)= (1/L1)+(1/L2)+(1/L3)

So (1/Leq) = (1/5m)+(1/4.3m)+(1/0.6m)

(1/Leq) = 2099.2248

Therefore

Leq = 1/2099.2248 = 0.47 mH

Which is less than 0.6 mH.

If the inductor are connected in parallel connection , then the formula for Equivalent Inductance is same as that of the Resistance.

i.e. (1/Leq)= (1/L1)+(1/L2)+(1/L3)

So (1/Leq) = (1/5m)+(1/4.3m)+(1/0.6m)

(1/Leq) = 2099.2248

Therefore

Leq = 1/2099.2248 = 0.47 mH

Which is less than 0.6 mH.

Satish kumar said:
1 decade ago

Ans:D

if the inductances(resistances) are connected in parallel,the equivalent inductances(resistances) will be less than the smaller individual inductance(resistance) coz... of the formula (1/Leq)=(1/L1)+(1/L2)+......+(1/Ln)

if the inductances(resistances) are connected in parallel,the equivalent inductances(resistances) will be less than the smaller individual inductance(resistance) coz... of the formula (1/Leq)=(1/L1)+(1/L2)+......+(1/Ln)

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