Electrical Engineering - Inductors - Discussion

Discussion Forum : Inductors - General Questions (Q.No. 4)
A 5 mH, a 4.3 mH, and a 0.6 mH inductor are connected in parallel. The total inductance is
9.9 mH
greater than 5 mH
9.9 mH or greater than 5 mH
less than 0.6 mH
Answer: Option
No answer description is available. Let's discuss.
7 comments Page 1 of 1.

Haseeb said:   3 years ago
The Equation. L = L2L3 + L1L3 + L1L2/L1L2L3.

Waseem said:   5 years ago
How to solve this? Please tell me.

D Shwetha said:   5 years ago

Your explanation is short & good. Thank you.

Soujanya said:   5 years ago
Thank you @Shivakumar K S.

SHIVAKUMAR K S said:   8 years ago
In any parallel combination of resistance or inductance the equivalent resistance or inductance is less than the least value of individual one.

Hence 0.6 is the least value in the combination of inductance in parallel.

ANS : 0.6.

Thirumal said:   1 decade ago
Ans : D
If the inductor are connected in parallel connection , then the formula for Equivalent Inductance is same as that of the Resistance.

i.e. (1/Leq)= (1/L1)+(1/L2)+(1/L3)

So (1/Leq) = (1/5m)+(1/4.3m)+(1/0.6m)
(1/Leq) = 2099.2248

Leq = 1/2099.2248 = 0.47 mH
Which is less than 0.6 mH.

Satish kumar said:   1 decade ago
if the inductances(resistances) are connected in parallel,the equivalent inductances(resistances) will be less than the smaller individual inductance(resistance) coz... of the formula (1/Leq)=(1/L1)+(1/L2)+......+(1/Ln)

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