Electrical Engineering - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 23)
23.
When the current through an inductor is cut in half, the amount of energy stored in the electromagnetic field
Discussion:
6 comments Page 1 of 1.
Sunny said:
9 years ago
Formula: W= 1/2 LI^2, inductor values kept same only current's value is cut into half or made half.
Example,
1) 1/2*6*10^2 = 300.
2) 1/2*6*5^2 = 75.
So 75/300 = 1/4 times decreased, that is quartered.
Example,
1) 1/2*6*10^2 = 300.
2) 1/2*6*5^2 = 75.
So 75/300 = 1/4 times decreased, that is quartered.
(1)
Pavan Korrapati said:
8 years ago
@Santhosh.
1/2LI^2means,
1/2*L*I^2=1/2*L*(1/2)^2=1/2*1/4*L=1/8
Because current is already cut in half i.e.,1/2.. But you said that, it is 1/4. How?
1/2LI^2means,
1/2*L*I^2=1/2*L*(1/2)^2=1/2*1/4*L=1/8
Because current is already cut in half i.e.,1/2.. But you said that, it is 1/4. How?
Santhosh said:
1 decade ago
Energy stored is 1/2 L I2.
If I is halved, energy stored gets reduced to 1/4 th.
If I is halved, energy stored gets reduced to 1/4 th.
HAris said:
6 years ago
Correct @Pavan.
The Energy will be 1/8th of L.
E=0.5Li^2,
E=0.5*L(0.5)^2,
E=(1/8)th of L.
The Energy will be 1/8th of L.
E=0.5Li^2,
E=0.5*L(0.5)^2,
E=(1/8)th of L.
Stuti kushwaha said:
10 years ago
I also agree to a/2 LI^2.
Dalitso said:
9 years ago
Nice and clear solutions.
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