Discussion :: Inductors - General Questions (Q.No.23)
| Santhosh said: (May 9, 2011) | |
| Energy stored is 1/2 L I2. If I is halved, energy stored gets reduced to 1/4 th. |
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| Stuti Kushwaha said: (Feb 15, 2016) | |
| I also agree to a/2 LI^2. | |
| Sunny said: (Mar 20, 2016) | |
| Formula: W= 1/2 LI^2, inductor values kept same only current's value is cut into half or made half. Example, 1) 1/2*6*10^2 = 300. 2) 1/2*6*5^2 = 75. So 75/300 = 1/4 times decreased, that is quartered. |
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| Dalitso said: (Aug 21, 2016) | |
| Nice and clear solutions. | |
| Pavan Korrapati said: (Dec 2, 2017) | |
| @Santhosh. 1/2LI^2means, 1/2*L*I^2=1/2*L*(1/2)^2=1/2*1/4*L=1/8 Because current is already cut in half i.e.,1/2.. But you said that, it is 1/4. How? |
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| Haris said: (Jan 11, 2020) | |
| Correct @Pavan. The Energy will be 1/8th of L. E=0.5Li^2, E=0.5*L(0.5)^2, E=(1/8)th of L. |
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