Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 5)
5.
A power supply produces a 0.6 W output with an input of 0.7 W. Its percentage of efficiency is
Discussion:
31 comments Page 3 of 4.
Baidya Nath Mohanta said:
1 decade ago
Efficiency = OP/IP *100.
= (0.6/0.7)*100.
= 85.7.
= (0.6/0.7)*100.
= 85.7.
Hemalatha said:
1 decade ago
@Hemalatha absolutely right the answer is 85.7%.
Jomel voltboy said:
1 decade ago
E = Output/Input*100.
E = 0.6/0.7*100.
E = 85.7%
E = 0.6/0.7*100.
E = 85.7%
Jeyaprabhu said:
2 years ago
Thanks everyone for explaining the answer.
Gambiza Absalom said:
8 years ago
Efficiency=Otput/Input X 100.
= 85.7%.
= 85.7%.
(1)
Hanumantappa said:
1 decade ago
Efficiency =o/p/i/p=0.6*100/0.7=8.71
Satyabrata said:
8 years ago
Efficiency = o.p/i.p * 100.
Ashok Kumar said:
3 years ago
(0.6 ÷ 0.7)*100= 85.7%.
(3)
Anomis said:
6 years ago
(0.6÷0.7)*100 = 85.7%.
(2)
Vinayak said:
1 decade ago
@Ankita Very nice.
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