Electrical Engineering - Energy and Power - Discussion

Discussion Forum : Energy and Power - General Questions (Q.No. 5)
5.
A power supply produces a 0.6 W output with an input of 0.7 W. Its percentage of efficiency is
8.57%
42.85%
4.28%
85.7%
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
31 comments Page 2 of 4.

Bhatruhari swain said:   1 decade ago
Efficiency = output/input.

= .6\.7.
= .857.

% efficiency = .857*100.
= 85.7%.

Sakthiraja m said:   7 years ago
Normally the efficiency formula is;

Efficiency =outputpower/inputpower * 100.
(1)

Ankita said:   1 decade ago
Efficiency=output/input

=. 6\.7
=. 857

% efficiency =. 857*100
= 85.7%

Babloo chandra said:   9 years ago
Efficiency = output/input.

= .6/.7.

= .857.

% = .857 * 100.

= 85.7%.

MUBIANA said:   10 years ago
Efficiency = (output/input)*100.

Efficiency = (0.6/0.7)*100.

= 85.7%.

Sivaprakash said:   1 decade ago
Efficiency = output power/ input power = (0.6/0.7)*100 = 85.71%

ANKITA said:   1 decade ago
E = O/I.
= 0.6/0.7.
= 0.857.

E OF 100 % = 0.857*100.
= 85.7%.

Diddikati Shiva prasad said:   9 months ago
Efficacy = Output/input ×100.

0.6/0.7 × 100 = 85.71%.
(2)

Alpesh kachhadiya said:   9 years ago
Efficiency = Output/Input.
So, E =.6/.7*100.
= 85.7%.

KANIKSADGIR said:   9 years ago
You gave a simple answer.

Thanks @Babloo Chandra.
(1)


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