Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 5)
5.
A power supply produces a 0.6 W output with an input of 0.7 W. Its percentage of efficiency is
Discussion:
31 comments Page 1 of 4.
Dayu said:
6 years ago
eff=output power/input power * 100.
So output power is 0.6w and input power is 0.7 watt.
0.6/0.7 * 100 = 85.7%.
So output power is 0.6w and input power is 0.7 watt.
0.6/0.7 * 100 = 85.7%.
(4)
Ashok Kumar said:
2 years ago
(0.6 ÷ 0.7)*100= 85.7%.
(2)
Anomis said:
5 years ago
(0.6÷0.7)*100 = 85.7%.
(2)
Diddikati Shiva prasad said:
2 weeks ago
Efficacy = Output/input ×100.
0.6/0.7 × 100 = 85.71%.
0.6/0.7 × 100 = 85.71%.
(1)
AliBaBa said:
5 years ago
Why no one has manually solved this 0.6/0.7 to get 0.857.
06/10 ÷ 07/10.
06/10 * 10/07 cross multiplication will cancel both 10.
06/07 = 0.857,
For efficiency, %age multiply it with 100.
= 85.7%.
06/10 ÷ 07/10.
06/10 * 10/07 cross multiplication will cancel both 10.
06/07 = 0.857,
For efficiency, %age multiply it with 100.
= 85.7%.
(1)
Sakthiraja m said:
6 years ago
Normally the efficiency formula is;
Efficiency =outputpower/inputpower * 100.
Efficiency =outputpower/inputpower * 100.
(1)
Gambiza Absalom said:
7 years ago
Efficiency=Otput/Input X 100.
= 85.7%.
= 85.7%.
(1)
KANIKSADGIR said:
8 years ago
You gave a simple answer.
Thanks @Babloo Chandra.
Thanks @Babloo Chandra.
(1)
Hemalatha said:
1 decade ago
@Hemalatha absolutely right the answer is 85.7%.
Jeyaprabhu said:
2 years ago
Thanks everyone for explaining the answer.
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