Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 5)
5.
A power supply produces a 0.6 W output with an input of 0.7 W. Its percentage of efficiency is
Discussion:
31 comments Page 2 of 4.
Satyabrata said:
8 years ago
Efficiency = o.p/i.p * 100.
Babloo chandra said:
9 years ago
Efficiency = output/input.
= .6/.7.
= .857.
% = .857 * 100.
= 85.7%.
= .6/.7.
= .857.
% = .857 * 100.
= 85.7%.
Alpesh kachhadiya said:
9 years ago
Efficiency = Output/Input.
So, E =.6/.7*100.
= 85.7%.
So, E =.6/.7*100.
= 85.7%.
MUBIANA said:
10 years ago
Efficiency = (output/input)*100.
Efficiency = (0.6/0.7)*100.
= 85.7%.
Efficiency = (0.6/0.7)*100.
= 85.7%.
Jomel voltboy said:
1 decade ago
E = Output/Input*100.
E = 0.6/0.7*100.
E = 85.7%
E = 0.6/0.7*100.
E = 85.7%
Baidya Nath Mohanta said:
1 decade ago
Efficiency = OP/IP *100.
= (0.6/0.7)*100.
= 85.7.
= (0.6/0.7)*100.
= 85.7.
Ankita said:
1 decade ago
Efficiency=output/input
=. 6\.7
=. 857
% efficiency =. 857*100
= 85.7%
=. 6\.7
=. 857
% efficiency =. 857*100
= 85.7%
Rani said:
1 decade ago
Option D was correct because the efficiency will be calculated by using formula (output/input).
So,
0.6/0.7 = 0.857.
Under % = 85.7%
So,
0.6/0.7 = 0.857.
Under % = 85.7%
Ramakanth said:
1 decade ago
E = output/input =output/output+losses.
So in the question they have to give that losses are neglected.
Then the answer is correct.
So in the question they have to give that losses are neglected.
Then the answer is correct.
ANKITA said:
1 decade ago
E = O/I.
= 0.6/0.7.
= 0.857.
E OF 100 % = 0.857*100.
= 85.7%.
= 0.6/0.7.
= 0.857.
E OF 100 % = 0.857*100.
= 85.7%.
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