Electrical Engineering - Energy and Power - Discussion

Answer is wrong. Because we doing in project side in small value of resistors are easily access the heat.

As per the given question both are equal wattage so given two resistors never get over heated. So the answer is option D.

Current is same through resisters connected in series.

The question has two key words: half-watt, and (connected) across. The resistors are designated to work up to half-watt power, more than it make them overheat. If the word across is used, it means the resistors are connected in parallel. Therefore,

R1 = 33 ohm, and its power dissipation is P1 = V*I1 = 12*12/33 = 4.3W.
R2 = 330 ohm, and its power dissipation is P2 = V*I2 = 12*12/330 = 0.43.
P1 = 4.3W>0.5W, and P2 = 0.43W<0.5W,

Hence, R1 = 33ohm is overheat, option A is the correct answer.

Since both resistors are connected across the voltage is in parallel so the option D is correct.

Less resistance more current and more current more heating.

Heated beyond a safe or desirable point is over heating so just pay attention on words of question when both are connected to same source and no external power conditions are changing then why are you so confuse Option D is ok.

Heating depends upon the amount of current flowing through each resistance, not on power. If considered in parallel arrangement, 33 ohm resistance has higher current flow so it should get overheated & option A should be correct.

Since they are connected in parallel and 33 ohm is very less than 330 ohm more current will flow through 33 ohm, and therefore more heat will dissipate across 33 ohm and it gets over heated.

Power consumed by each of them is same so both of them get equally heated.