Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 1)
1.
A 33 
half-watt resistor and a 330 half-watt resistor are connected across a 12 V source. Which one(s) will overheat?
half-watt resistor and a 330 half-watt resistor are connected across a 12 V source. Which one(s) will overheat?33
330
both resistors
neither resistor
Discussion:
58 comments Page 3 of 6.
CHAVITINA RAMAKRISHNA said:
9 years ago
Equal rating not given, why you people calling equal rating?
Sonu kumar said:
9 years ago
Because both the resistor has equal rating and heating of resistor depends on wattage only. Not on the type of connection.
S K Pillai said:
9 years ago
Question should be more clear. Whether the resistances are in series or in parallel? The answer differs D or A.
Stuti kushwaha said:
10 years ago
Option A should be correct according to i^2r we see that more current flow through 33 ohm. So more heat should across it.
Marshall said:
10 years ago
Both load are resistive components. It dissipate power. For sure both of them will produce heat. So both of them.
Arun said:
10 years ago
33 ohm will draw more current compared to 330 ohm, since they are connected in parallel 12 remains fixed across both but current gets splitted according to the resistance opposed, obviously 330 will oppose more current hence will dissipate less while 33 will draw in more current thus dissipating heat more, if any mistake please clarify me.
Pratap Kumar said:
10 years ago
Heat is I^2R. This loss is more in 33 ohm resistor. Option A is correct.
Oorja said:
10 years ago
I agree that the connection is not clear. If connected in series then option D otherwise option A.
Akhil said:
1 decade ago
It should be "B" because in both resisters power is same i.e, 0.5 w.
So 330 R will have high power loss i^2*r than the 33 R.
So 330 R will have high power loss i^2*r than the 33 R.
Munawar said:
1 decade ago
It is [A] 33 W will overheat, because its wattage VI = 12*12/33 = 4.36 W against the allowed 0.5 W. For 330 W, wattage = 12*12/330 = 0.436 W within the 0.5 W.
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