Electrical Engineering - Circuit Theorems in AC Analysis - Discussion
Discussion Forum : Circuit Theorems in AC Analysis - General Questions (Q.No. 3)
3.
Referring to the given circuit, find ZTH if R is 15 k
and RL is 38 k.
and RL is 38 k.
89.82 
–51.3° k
–51.3° k19.2 –38.3° k
–38.3° k9.38–51.3° k
–51.3° k180 –38.3° k
–38.3° kDiscussion:
11 comments Page 1 of 2.
Shashwat said:
1 decade ago
Its not provided in the question that the Zth has to be found across which branch.
Nikhil jain said:
1 decade ago
The parallel combination of j12 and 15 will give the answer.
Vasiq said:
1 decade ago
15? You mean 8k?
RICHA DHINGRA said:
1 decade ago
Zth is found across load so RL will open circuit and voltage source short circuit so XL will also SC. So XC and are will become parallel to each other and gave answer.
Ali Mohamed said:
1 decade ago
@Vasiq he said to replace 8K with 15K.
(2)
Chinni krishna said:
9 years ago
Can anyone tell which is the correct answer.
(1)
Abdi said:
9 years ago
First short the Vs. Since Vs is in parallel with Xl, Xl goes to zero.
Second remove the Rl by opening it.that is the point where Zth is found. Now R (8K) is in parallel with Xc.
Zth = Xc//R = j12*15 / (j12 + 15) = 9.37<theta = 51.34>
Second remove the Rl by opening it.that is the point where Zth is found. Now R (8K) is in parallel with Xc.
Zth = Xc//R = j12*15 / (j12 + 15) = 9.37<theta = 51.34>
(1)
Ahmad ado said:
9 years ago
How to work out the solution?
Rajeeb giri said:
8 years ago
Can tell which is the correct answer?
(1)
Sashank said:
6 years ago
The answer is 9.3θ +51.3°.
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