Electrical Engineering - Circuit Theorems in AC Analysis - Discussion

Discussion Forum : Circuit Theorems in AC Analysis - General Questions (Q.No. 3)
3.
Referring to the given circuit, find ZTH if R is 15 k and RL is 38 k.

89.82 –51.3° k
19.2 –38.3° k
9.38–51.3° k
180 –38.3° k
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Yu Wei said:   3 years ago
In getting Zth all resistors must be considered.

1. However, XL is in parallel with 0 ohms (shorted part of the source), making it also zero so it will be disregarded.
4(0)/4+0 = 0

2. If not stated, automatically consider RL as your Vout, thus it's open.

3. This will leave us with Xc/R.
4. ZTH = 9.37 ∠ 51.3°.

Sashank said:   6 years ago
The answer is 9.3θ +51.3°.

Rajeeb giri said:   8 years ago
Can tell which is the correct answer?
(1)

Ahmad ado said:   9 years ago
How to work out the solution?

Abdi said:   9 years ago
First short the Vs. Since Vs is in parallel with Xl, Xl goes to zero.

Second remove the Rl by opening it.that is the point where Zth is found. Now R (8K) is in parallel with Xc.

Zth = Xc//R = j12*15 / (j12 + 15) = 9.37<theta = 51.34>
(1)

Chinni krishna said:   9 years ago
Can anyone tell which is the correct answer.
(1)

Ali Mohamed said:   1 decade ago
@Vasiq he said to replace 8K with 15K.
(2)

RICHA DHINGRA said:   1 decade ago
Zth is found across load so RL will open circuit and voltage source short circuit so XL will also SC. So XC and are will become parallel to each other and gave answer.

Vasiq said:   1 decade ago
15? You mean 8k?

Nikhil jain said:   1 decade ago
The parallel combination of j12 and 15 will give the answer.


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