Electrical Engineering - Circuit Theorems in AC Analysis - Discussion
Discussion Forum : Circuit Theorems in AC Analysis - General Questions (Q.No. 1)
1.
Determine VTH when R1 is 180 
and XL is 90 .
and XL is 90 .
135
63.4° V
63.4° V13.563.4° V
63.4° V12.20° V
0° V1220° V
0° VDiscussion:
16 comments Page 1 of 2.
DHANANJAY said:
1 decade ago
This can be solved simply.
First find total impedance "Z" then current in the branch.
Then multiply with the inductor reactance that is X.
z = sqrt of (R^2 + X^2) where R = resistance = 180 and X = reactant = 90.
Solve it.
Find i = supply voltage/impedance (Z) = 30/calculated z.
Now to get Vth multiply calculated current with reactance (x=90).
Then to find phase angle we know that tan Q = x/r.
First find total impedance "Z" then current in the branch.
Then multiply with the inductor reactance that is X.
z = sqrt of (R^2 + X^2) where R = resistance = 180 and X = reactant = 90.
Solve it.
Find i = supply voltage/impedance (Z) = 30/calculated z.
Now to get Vth multiply calculated current with reactance (x=90).
Then to find phase angle we know that tan Q = x/r.
(2)
Cherry said:
1 decade ago
Simply replace with 180 and 90 and solve
1st find out the current in the loop ...to find Vth
1. 30/sqrtof(180 and 90) with angle ll get
2. then multiply with Xl to get Vth
0.15*90 at angle 90
Ans.13.25 at an angle 63.4
1st find out the current in the loop ...to find Vth
1. 30/sqrtof(180 and 90) with angle ll get
2. then multiply with Xl to get Vth
0.15*90 at angle 90
Ans.13.25 at an angle 63.4
Nikhil Jain said:
1 decade ago
Can't be (A) , load voltage is higher than the source.
Can't be (C) or (D) , as the phase angle is zero.
Even without doing the calculations, it has to be (B).
Can't be (C) or (D) , as the phase angle is zero.
Even without doing the calculations, it has to be (B).
(1)
Gary said:
1 decade ago
Can't be (A), load voltage is higher than the source.
Can't be (C) or (D), as the phase angle is zero.
Even without doing the calculations, it has to be (B).
Can't be (C) or (D), as the phase angle is zero.
Even without doing the calculations, it has to be (B).
Riya said:
6 years ago
Actually, l is inductance but xl is the impedance of that device. Impedance is simply resistance. Hence it is in ohms.
(1)
Jai said:
1 decade ago
voltage across A-B = Voltage across XL = Vth.
By volt div. rule,
Vth = (30*j90)/(180+j90).
= 13.5 ang(63.4).
By volt div. rule,
Vth = (30*j90)/(180+j90).
= 13.5 ang(63.4).
(5)
Vasiq said:
1 decade ago
@Jai.
That is not correct. 90 is the value of the resistor and, hence, shouldn't have a joint in front of it.
That is not correct. 90 is the value of the resistor and, hence, shouldn't have a joint in front of it.
Bruce said:
9 years ago
In a 3 phase cct, 380v, 1 breaker per phase. Q: when all breakers powered, they all trip, why?
(2)
RAVINDER said:
9 years ago
By using volt division rule Vab = Vs * XL/ (R1 + XL) which give Vab = 10V.
(2)
Nikhil jain said:
1 decade ago
The value of inductance should be given in the form of j or in henry.
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