Electrical Engineering - Circuit Theorems in AC Analysis - Discussion

Discussion Forum : Circuit Theorems in AC Analysis - General Questions (Q.No. 1)
1.
Determine VTH when R1 is 180 and XL is 90 .

13563.4° V
13.563.4° V
12.20° V
1220° V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 1 of 2.

Jai said:   1 decade ago
voltage across A-B = Voltage across XL = Vth.

By volt div. rule,

Vth = (30*j90)/(180+j90).

= 13.5 ang(63.4).
(5)

DHANANJAY said:   1 decade ago
This can be solved simply.

First find total impedance "Z" then current in the branch.

Then multiply with the inductor reactance that is X.

z = sqrt of (R^2 + X^2) where R = resistance = 180 and X = reactant = 90.

Solve it.

Find i = supply voltage/impedance (Z) = 30/calculated z.

Now to get Vth multiply calculated current with reactance (x=90).

Then to find phase angle we know that tan Q = x/r.
(2)

RAVINDER said:   9 years ago
By using volt division rule Vab = Vs * XL/ (R1 + XL) which give Vab = 10V.
(2)

Bruce said:   9 years ago
In a 3 phase cct, 380v, 1 breaker per phase. Q: when all breakers powered, they all trip, why?
(2)

Nikhil Jain said:   1 decade ago
Can't be (A) , load voltage is higher than the source.

Can't be (C) or (D) , as the phase angle is zero.

Even without doing the calculations, it has to be (B).
(1)

Riya said:   6 years ago
Actually, l is inductance but xl is the impedance of that device. Impedance is simply resistance. Hence it is in ohms.
(1)

Anand m said:   1 decade ago
I want no the explanation for this quation.

Alfredo said:   1 decade ago
Why is XL given in ohms? Shouldn't it be henries?

James said:   1 decade ago
Xl also has some form of resistance

Cherry said:   1 decade ago
Simply replace with 180 and 90 and solve
1st find out the current in the loop ...to find Vth
1. 30/sqrtof(180 and 90) with angle ll get
2. then multiply with Xl to get Vth
0.15*90 at angle 90
Ans.13.25 at an angle 63.4


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