Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 6)
6.
Determine IN for the circuit consisting of VS, R1, R2, and R3 shown in the given circuit.
Discussion:
20 comments Page 1 of 2.
Paresh khatri said:
8 years ago
IN means Norton current.
(3)
Sankararao mamidi said:
1 decade ago
Apply nodal equation to the circuit.
[v-75]/68+v/68+v/120 = 0.
We get v = 29.22.
In = v/r.
In = 29.22/120.
In = 0.2435A.
[v-75]/68+v/68+v/120 = 0.
We get v = 29.22.
In = v/r.
In = 29.22/120.
In = 0.2435A.
(3)
Anand said:
1 decade ago
In is the Norton Equivalent current source, to find that :
Short the points A-B and then find the current drawn from the source. This gives the value of In. Answer comes out to be 673.22mA, close to A.
Short the points A-B and then find the current drawn from the source. This gives the value of In. Answer comes out to be 673.22mA, close to A.
(2)
Ankur said:
10 years ago
It can be solved by Thevenin's theorem. But have to ignore value of RL in equation. IL = vth/Rth+RL.
(1)
Seema said:
1 decade ago
Apply to KVL & solve it.
equations are:-
75-68I1-68I2=0.......(i)
-120I1+188I2=0.......(ii)
solve two equations....& same current flow in R3 & RL
i.e. I1-I2=242mA (Approx.)
equations are:-
75-68I1-68I2=0.......(i)
-120I1+188I2=0.......(ii)
solve two equations....& same current flow in R3 & RL
i.e. I1-I2=242mA (Approx.)
(1)
Jeffrey said:
1 decade ago
It means Norton Current.
(1)
Tes said:
1 decade ago
I think you should use thevnin theorem. That means find Vn by opening AB and find Rn by shorting AB. Finally divide Vn / Rn = In.
Akshaykumar said:
6 years ago
Apply KCL to both loop, then solve those two equations, then the current i2 will be the answer, i.e=0.436A.
Prosper said:
8 years ago
RL represent the Load, using nortons theorem, you remove the load and find the current through R3.
Mathireesan said:
1 decade ago
IN means?
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