Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 6)
6.
Determine IN for the circuit consisting of VS, R1, R2, and R3 shown in the given circuit.
Discussion:
20 comments Page 2 of 2.
ASHISH NAUTIYAL said:
1 decade ago
From nodal equation.
(v-75)/68+v/68+v/120 = 0.
By solving this we get v = 29.22.
Now by ohm's law to 120 ohm resistor.
IN = v/r = 29.22/120 = 0.244A.
or 1A = 1000mA.
SO, 0.244*1000 = 244mA.
(v-75)/68+v/68+v/120 = 0.
By solving this we get v = 29.22.
Now by ohm's law to 120 ohm resistor.
IN = v/r = 29.22/120 = 0.244A.
or 1A = 1000mA.
SO, 0.244*1000 = 244mA.
Dishant said:
1 decade ago
It's simple. Just short AB & apply kvl.
Shekhar said:
1 decade ago
What is value of RL?
Karan saini said:
1 decade ago
Apply Thevenin Theorem-
finding Vth by nodal method
V-75/68+V/68=0
V=37.5
ten find Rth
Rth=(R1//R2)+R3
Rth=154ohm
In=37.5/154
In=244mA
Answer B is right
245mA is nearly 244mA
finding Vth by nodal method
V-75/68+V/68=0
V=37.5
ten find Rth
Rth=(R1//R2)+R3
Rth=154ohm
In=37.5/154
In=244mA
Answer B is right
245mA is nearly 244mA
Arundeep singh said:
1 decade ago
Rt = R1+ (R2*R3/R2+R3) = 68+ (68*120/68+120) =111.4 ohm.
It = Vs/Rt = 75/111.4 = 673 mA.
In = (R2/R2+R3) It = (68/68+120) 673 = 243.42 mA.
So answer B is absolutely right.
Rt=total resistance, It= total current, In = Norton's current).
It = Vs/Rt = 75/111.4 = 673 mA.
In = (R2/R2+R3) It = (68/68+120) 673 = 243.42 mA.
So answer B is absolutely right.
Rt=total resistance, It= total current, In = Norton's current).
Richard said:
1 decade ago
Guys from the nortons theorem that I know, In is supposed to be the current through the short circuit at AB.
That implies that is obtained from current through the 120ohm resistance which by current divider rule is.
(68/ (120+68) ) of the net current supllied by 75 voltage source.
Please correct me if I'm wrong!
That implies that is obtained from current through the 120ohm resistance which by current divider rule is.
(68/ (120+68) ) of the net current supllied by 75 voltage source.
Please correct me if I'm wrong!
M.V.KRISHNA/PALVONCHA said:
1 decade ago
In=Vn/Rn.
Vn=(Vs*R2)/(R1+R2)
Vn=37.5v
Rn=R3+(R1//R2)
Rn=150 ohm
In=37.5/150
In=0.25A =250 mA (approx. equal to option B)
Vn=(Vs*R2)/(R1+R2)
Vn=37.5v
Rn=R3+(R1//R2)
Rn=150 ohm
In=37.5/150
In=0.25A =250 mA (approx. equal to option B)
Hanumantha said:
1 decade ago
By nortan,s Theorem
Tirumala rao said:
1 decade ago
Solve the problem. I want explanation?
Kumar said:
1 decade ago
Tell me that how to calculate the In ?
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