Electrical Engineering - Circuit Theorems and Conversions - Discussion

Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 2)
2.
A certain current source has the values IS = 4 µA and RS = 1.2 M. The values for an equivalent voltage source are
4.8 V, 1.2 M
1 V, 1.2 M
4.8 V, 4.8 M
4.8 V, 1.2 M
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 1 of 2.

Janmejay said:   1 decade ago
v(s)=i(s)*r(s)

Bharat said:   1 decade ago
As a ohms law is V=IR we will ge the voltage as 4.8v option 4 is right.

Sabari said:   1 decade ago
V = IR.

V = (4*10^-6)(1.2*10^6).

V = (4*1.2)=4.8V.

Naveed said:   1 decade ago
@Sabari @Bharat @Janmejay your procedure is not correct.

P = VI = V^2/R = I^2*R.

P = 4.8^2/1.2*10^6 = 1.92*10^-5.

So option D is correct.

Fan said:   1 decade ago
@Naveed.

What's power got to do with the problem?

Mounika pati said:   1 decade ago
As we know from Ohms Law,

V = IR.

= (4*10^-6)*(1.2*10^6).

= 4.8v.

''Voltage = 4.8v''.

Tinnu said:   1 decade ago
There are two options with 4.8v so by calculating power we can get right option.

Zaim said:   1 decade ago
How to calculate the resistance of voltage source?

Yugal Kishor Bairagi said:   1 decade ago
Given data:-

I = 4 micro Amps.

R = 1.2 Mega Ohms.

V = IR.

So, V = 4*1.2 = 4.8 V.

(where micro & mega is cancel out, because micro means 10 the power minus -6 & mega means 10 the power plus +6).

Sana said:   8 years ago
I = 4 micro Amps.

R = 1.2 Mega Ohms.

V = IR.
So, V = 4*1.2 = 4.8 V.
in options 2nd is the resistance so, by using this vtg we can find r=4.8/4*10^-6=1.2 Mohm.
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