Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 2)
2.
A certain current source has the values IS = 4 µA and RS = 1.2 M
. The values for an equivalent voltage source are

Discussion:
13 comments Page 1 of 2.
Janmejay said:
1 decade ago
v(s)=i(s)*r(s)
Bharat said:
1 decade ago
As a ohms law is V=IR we will ge the voltage as 4.8v option 4 is right.
Sabari said:
1 decade ago
V = IR.
V = (4*10^-6)(1.2*10^6).
V = (4*1.2)=4.8V.
V = (4*10^-6)(1.2*10^6).
V = (4*1.2)=4.8V.
Naveed said:
1 decade ago
@Sabari @Bharat @Janmejay your procedure is not correct.
P = VI = V^2/R = I^2*R.
P = 4.8^2/1.2*10^6 = 1.92*10^-5.
So option D is correct.
P = VI = V^2/R = I^2*R.
P = 4.8^2/1.2*10^6 = 1.92*10^-5.
So option D is correct.
Fan said:
1 decade ago
@Naveed.
What's power got to do with the problem?
What's power got to do with the problem?
Mounika pati said:
1 decade ago
As we know from Ohms Law,
V = IR.
= (4*10^-6)*(1.2*10^6).
= 4.8v.
''Voltage = 4.8v''.
V = IR.
= (4*10^-6)*(1.2*10^6).
= 4.8v.
''Voltage = 4.8v''.
Tinnu said:
1 decade ago
There are two options with 4.8v so by calculating power we can get right option.
Zaim said:
1 decade ago
How to calculate the resistance of voltage source?
Yugal Kishor Bairagi said:
1 decade ago
Given data:-
I = 4 micro Amps.
R = 1.2 Mega Ohms.
V = IR.
So, V = 4*1.2 = 4.8 V.
(where micro & mega is cancel out, because micro means 10 the power minus -6 & mega means 10 the power plus +6).
I = 4 micro Amps.
R = 1.2 Mega Ohms.
V = IR.
So, V = 4*1.2 = 4.8 V.
(where micro & mega is cancel out, because micro means 10 the power minus -6 & mega means 10 the power plus +6).
Sana said:
8 years ago
I = 4 micro Amps.
R = 1.2 Mega Ohms.
V = IR.
So, V = 4*1.2 = 4.8 V.
in options 2nd is the resistance so, by using this vtg we can find r=4.8/4*10^-6=1.2 Mohm.
R = 1.2 Mega Ohms.
V = IR.
So, V = 4*1.2 = 4.8 V.
in options 2nd is the resistance so, by using this vtg we can find r=4.8/4*10^-6=1.2 Mohm.
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