Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 2)
2.
A certain current source has the values IS = 4 µA and RS = 1.2 M
. The values for an equivalent voltage source are
. The values for an equivalent voltage source are4.8 
V, 1.2 M
V, 1.2 M1 V, 1.2 M
4.8 V, 4.8 M
4.8 V, 1.2 M
Discussion:
13 comments Page 1 of 2.
Hidden Tesla said:
6 years ago
Using Source Conversion Theorems.
Current Source Converted to Voltage Source - Vs = Is*Rs=4*1.2 = 4.8V.
Now Rs = 1.2Mohm Connected Series with Voltage source.
Current Source Converted to Voltage Source - Vs = Is*Rs=4*1.2 = 4.8V.
Now Rs = 1.2Mohm Connected Series with Voltage source.
(3)
Ramza said:
7 years ago
Apply Ohm's law to find voltage.
And there will be no change in resistance.
V=IR,
V=4.8V,
R=1.2Mohms.
And there will be no change in resistance.
V=IR,
V=4.8V,
R=1.2Mohms.
(2)
Kusal said:
8 years ago
This is a case.
Convert current source to voltage source.
So voltage is 4.8 & resistance is no change.
Convert current source to voltage source.
So voltage is 4.8 & resistance is no change.
Sana said:
8 years ago
I = 4 micro Amps.
R = 1.2 Mega Ohms.
V = IR.
So, V = 4*1.2 = 4.8 V.
in options 2nd is the resistance so, by using this vtg we can find r=4.8/4*10^-6=1.2 Mohm.
R = 1.2 Mega Ohms.
V = IR.
So, V = 4*1.2 = 4.8 V.
in options 2nd is the resistance so, by using this vtg we can find r=4.8/4*10^-6=1.2 Mohm.
(1)
Yugal Kishor Bairagi said:
1 decade ago
Given data:-
I = 4 micro Amps.
R = 1.2 Mega Ohms.
V = IR.
So, V = 4*1.2 = 4.8 V.
(where micro & mega is cancel out, because micro means 10 the power minus -6 & mega means 10 the power plus +6).
I = 4 micro Amps.
R = 1.2 Mega Ohms.
V = IR.
So, V = 4*1.2 = 4.8 V.
(where micro & mega is cancel out, because micro means 10 the power minus -6 & mega means 10 the power plus +6).
Zaim said:
1 decade ago
How to calculate the resistance of voltage source?
Tinnu said:
1 decade ago
There are two options with 4.8v so by calculating power we can get right option.
Mounika pati said:
1 decade ago
As we know from Ohms Law,
V = IR.
= (4*10^-6)*(1.2*10^6).
= 4.8v.
''Voltage = 4.8v''.
V = IR.
= (4*10^-6)*(1.2*10^6).
= 4.8v.
''Voltage = 4.8v''.
Fan said:
1 decade ago
@Naveed.
What's power got to do with the problem?
What's power got to do with the problem?
Naveed said:
1 decade ago
@Sabari @Bharat @Janmejay your procedure is not correct.
P = VI = V^2/R = I^2*R.
P = 4.8^2/1.2*10^6 = 1.92*10^-5.
So option D is correct.
P = VI = V^2/R = I^2*R.
P = 4.8^2/1.2*10^6 = 1.92*10^-5.
So option D is correct.
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