Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 15)
15.
A 2
RL is connected across a voltage source, VS, of 110 V. The source's internal resistance is 24
. What is the output voltage across the load?


Discussion:
3 comments Page 1 of 1.
Goutham.B said:
9 years ago
Voltage divider rule.
= (main voltage * resistance of the same branch)/sum of resistances.
= (110 * 2)/(24 + 2) = 8.46.
= (main voltage * resistance of the same branch)/sum of resistances.
= (110 * 2)/(24 + 2) = 8.46.
Arundeep singh said:
1 decade ago
Vout = 110*2/ (2+24).
Vout = 8.46 = 8.5
Answer A is right.
Vout = 8.46 = 8.5
Answer A is right.
Suvo said:
9 years ago
Please, anyone give more explanation.
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