Electrical Engineering - Circuit Theorems and Conversions - Discussion

Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 15)
15.
A 2 RL is connected across a voltage source, VS, of 110 V. The source's internal resistance is 24 . What is the output voltage across the load?
8.5 V
85 V
0 V
110 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
3 comments Page 1 of 1.

Goutham.B said:   9 years ago
Voltage divider rule.

= (main voltage * resistance of the same branch)/sum of resistances.
= (110 * 2)/(24 + 2) = 8.46.

Arundeep singh said:   1 decade ago
Vout = 110*2/ (2+24).

Vout = 8.46 = 8.5

Answer A is right.

Suvo said:   9 years ago
Please, anyone give more explanation.

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