Electrical Engineering - Circuit Theorems and Conversions - Discussion

Discussion :: Circuit Theorems and Conversions - General Questions (Q.No.15)

15. 

A 2 RL is connected across a voltage source, VS, of 110 V. The source's internal resistance is 24 . What is the output voltage across the load?

[A]. 8.5 V
[B]. 85 V
[C]. 0 V
[D]. 110 V

Answer: Option A

Explanation:

No answer description available for this question.

Arundeep Singh said: (Jun 27, 2012)  
Vout = 110*2/ (2+24).

Vout = 8.46 = 8.5

Answer A is right.

Suvo said: (Nov 23, 2016)  
Please, anyone give more explanation.

Goutham.B said: (Dec 18, 2016)  
Voltage divider rule.

= (main voltage * resistance of the same branch)/sum of resistances.
= (110 * 2)/(24 + 2) = 8.46.

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