Electrical Engineering - Capacitors - Discussion

Discussion Forum : Capacitors - General Questions (Q.No. 19)
19.
A 2 F, a 4 F, and a 10 F capacitor are connected in series. The total capacitance is less than
2 F
4 F
10 F
1.5 F
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Precious said:   8 years ago
According to me, the correct answer with the given values will be A=2.
(1)

Md.Tanim dewan said:   8 years ago
Total series capacitance always less than the individual smallest capacitance.
(1)

Lochana said:   1 decade ago
Total capacitance = 1/C1 + 1/C2 + 1/C3
Total capacitance = 1.2 micro farads approx.
Hence it is less than 1.5 micro farads.

Sundar said:   1 decade ago
Series Capacitors Equation

1/C(tot) = 1/C1 + 1/C2 + 1/C3 + ...

When adding together Capacitors in Series, the reciprocal (1/C) of the individual capacitors are all added together (just like resistors in parallel) instead of the capacitances themselves. Then the total value for capacitors in series equals the reciprocal of the sum of the reciprocals of the individual capacitances.

Muhammad qaiser said:   1 decade ago
Because in series capacitors equation is ct= 1/C1+ 1/C2+ 1/C3.

Jeet Sengupta said:   1 decade ago
1/Ceq = 1/2+1/4+1/10 = (10+5+2) /20 = 17/20.

Therefore, Ceq = 20/17 = 1.176>1.15.

So correct answer will be A.

SONU KUMAR said:   1 decade ago
Adding the capacitance in series will give less value than minimum capacitance.

1/c = 1/c1+1/c2+...

Suvo said:   9 years ago
Total capacitance is less than all of the capacitance.

Md. Rayhan Uddin said:   8 years ago
1/C=1/2+1/4+1/10.
=>1/C=(10+5+2)*20,
=>1/C=17/20.
=>C=20/17=1.18<1.5.

Rajesh said:   7 years ago
@Rayhan Uddin.

Why you multiple by 20?

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