Electrical Engineering - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 19)
19.
A 2 
F, a 4 F, and a 10 F capacitor are connected in series. The total capacitance is less than
F, a 4 F, and a 10 F capacitor are connected in series. The total capacitance is less than2 F
F4 F
F10 F
F1.5 F
FDiscussion:
10 comments Page 1 of 1.
Rajesh said:
7 years ago
@Rayhan Uddin.
Why you multiple by 20?
Why you multiple by 20?
Md.Tanim dewan said:
8 years ago
Total series capacitance always less than the individual smallest capacitance.
(1)
Md. Rayhan Uddin said:
8 years ago
1/C=1/2+1/4+1/10.
=>1/C=(10+5+2)*20,
=>1/C=17/20.
=>C=20/17=1.18<1.5.
=>1/C=(10+5+2)*20,
=>1/C=17/20.
=>C=20/17=1.18<1.5.
Precious said:
8 years ago
According to me, the correct answer with the given values will be A=2.
(1)
Suvo said:
9 years ago
Total capacitance is less than all of the capacitance.
SONU KUMAR said:
1 decade ago
Adding the capacitance in series will give less value than minimum capacitance.
1/c = 1/c1+1/c2+...
1/c = 1/c1+1/c2+...
Jeet Sengupta said:
1 decade ago
1/Ceq = 1/2+1/4+1/10 = (10+5+2) /20 = 17/20.
Therefore, Ceq = 20/17 = 1.176>1.15.
So correct answer will be A.
Therefore, Ceq = 20/17 = 1.176>1.15.
So correct answer will be A.
Muhammad qaiser said:
1 decade ago
Because in series capacitors equation is ct= 1/C1+ 1/C2+ 1/C3.
Sundar said:
1 decade ago
Series Capacitors Equation
1/C(tot) = 1/C1 + 1/C2 + 1/C3 + ...
When adding together Capacitors in Series, the reciprocal (1/C) of the individual capacitors are all added together (just like resistors in parallel) instead of the capacitances themselves. Then the total value for capacitors in series equals the reciprocal of the sum of the reciprocals of the individual capacitances.
1/C(tot) = 1/C1 + 1/C2 + 1/C3 + ...
When adding together Capacitors in Series, the reciprocal (1/C) of the individual capacitors are all added together (just like resistors in parallel) instead of the capacitances themselves. Then the total value for capacitors in series equals the reciprocal of the sum of the reciprocals of the individual capacitances.
Lochana said:
1 decade ago
Total capacitance = 1/C1 + 1/C2 + 1/C3
Total capacitance = 1.2 micro farads approx.
Hence it is less than 1.5 micro farads.
Total capacitance = 1.2 micro farads approx.
Hence it is less than 1.5 micro farads.
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