Digital Electronics - Signals and Switches - Discussion
Discussion Forum : Signals and Switches - General Questions (Q.No. 4)
4.
The hexadecimal number 4B16 is transmitted as an 8-bit word in parallel. What is the time required for this transmission if the clock frequency is 2.25 MHz?
444 ns
444 
s
s3.55 s
s3.55 ms
Discussion:
5 comments Page 1 of 1.
Abc said:
8 years ago
f = 2.25 MHz (given),
t = 1/f,
t = 1/(2.25 x 10^6) = 0.4444... X 10^-6 => 444 x 10^-9 => 444ns.
t = 1/f,
t = 1/(2.25 x 10^6) = 0.4444... X 10^-6 => 444 x 10^-9 => 444ns.
Gulshan kumari said:
9 years ago
Please explain in detail.
Vivek said:
1 decade ago
Because the clock pulse of 4-bit transmit the data of 8-bit word
in parallel mode.
And this transmission done at 2.25mhz frequency.
we know that;
f=1/t
and we can find the time required for this transmission by the clock pulse
in parallel mode.
And this transmission done at 2.25mhz frequency.
we know that;
f=1/t
and we can find the time required for this transmission by the clock pulse
M.Arul said:
1 decade ago
Because the date transmit in parallel manner by 8 bit word, the no contain 32 bits, so 4 clock pulse need for transmission.
Mini said:
1 decade ago
Thats because data is being transmitted in a parallel manner, so it would take only one clock pulse to transmit whole data.
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