Digital Electronics - Signals and Switches - Discussion

Discussion :: Signals and Switches - General Questions (Q.No.4)


The hexadecimal number 4B16 is transmitted as an 8-bit word in parallel. What is the time required for this transmission if the clock frequency is 2.25 MHz?

[A]. 444 ns
[B]. 444 s
[C]. 3.55 s
[D]. 3.55 ms

Answer: Option A


No answer description available for this question.

Mini said: (Sep 2, 2011)  
Thats because data is being transmitted in a parallel manner, so it would take only one clock pulse to transmit whole data.

M.Arul said: (Feb 13, 2012)  
Because the date transmit in parallel manner by 8 bit word, the no contain 32 bits, so 4 clock pulse need for transmission.

Vivek said: (Aug 23, 2012)  
Because the clock pulse of 4-bit transmit the data of 8-bit word
in parallel mode.
And this transmission done at 2.25mhz frequency.
we know that;
and we can find the time required for this transmission by the clock pulse

Gulshan Kumari said: (Jun 27, 2015)  
Please explain in detail.

Abc said: (Jul 29, 2016)  
f = 2.25 MHz (given),
t = 1/f,
t = 1/(2.25 x 10^6) = 0.4444... X 10^-6 => 444 x 10^-9 => 444ns.

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