Digital Electronics - Shift Registers - Discussion
Discussion Forum : Shift Registers - General Questions (Q.No. 13)
13.
The group of bits 11001 is serially shifted (right-most bit first) into a 5-bit parallel output shift register with an initial state 01110. After three clock pulses, the register contains ________.
Discussion:
12 comments Page 1 of 2.
Rakesh said:
8 years ago
It is give right most bit is first 11001.
11001/01110,
1100/10111->1st clk pulse.
110/01011->2nd clk pulse.
11/00101->3rd Clo pulse.
11001/01110,
1100/10111->1st clk pulse.
110/01011->2nd clk pulse.
11/00101->3rd Clo pulse.
(4)
Chintu said:
1 decade ago
LSB bit is inverted and feed back to MSB.
01110->initial.
10111->first clk pulse.
01011->second.
00101->third.
01110->initial.
10111->first clk pulse.
01011->second.
00101->third.
(2)
Amit said:
9 years ago
How you know its a johnson counter.
(1)
Honey said:
5 years ago
Thanks @Rakesh.
(1)
Shilpa said:
1 decade ago
How the answer contains 3 zeros?
David said:
1 decade ago
It is given that right most bit is first of 11001.
Initial state is 01110.
11001 01110.
10111.
01011.
00101.
So answer is after three clock pulse 00101.
Initial state is 01110.
11001 01110.
10111.
01011.
00101.
So answer is after three clock pulse 00101.
Prakash said:
1 decade ago
Couldn't understand. Please will you elaborate it.
Shruti said:
5 years ago
Thank you so much @Rakesh.
K.Malathi said:
4 years ago
Thank you so much @Rakesh.
Divya said:
4 years ago
Thank you @Rakesh.
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