Digital Electronics - Shift Registers - Discussion
Discussion Forum : Shift Registers - General Questions (Q.No. 13)
13.
The group of bits 11001 is serially shifted (right-most bit first) into a 5-bit parallel output shift register with an initial state 01110. After three clock pulses, the register contains ________.
Discussion:
12 comments Page 1 of 2.
Priyanka said:
3 years ago
Thank you @Rakesh.
Afiq said:
4 years ago
Thank you @Rakesh.
Divya said:
4 years ago
Thank you @Rakesh.
K.Malathi said:
4 years ago
Thank you so much @Rakesh.
Shruti said:
5 years ago
Thank you so much @Rakesh.
Honey said:
5 years ago
Thanks @Rakesh.
(1)
Rakesh said:
8 years ago
It is give right most bit is first 11001.
11001/01110,
1100/10111->1st clk pulse.
110/01011->2nd clk pulse.
11/00101->3rd Clo pulse.
11001/01110,
1100/10111->1st clk pulse.
110/01011->2nd clk pulse.
11/00101->3rd Clo pulse.
(4)
Amit said:
9 years ago
How you know its a johnson counter.
(1)
Chintu said:
1 decade ago
LSB bit is inverted and feed back to MSB.
01110->initial.
10111->first clk pulse.
01011->second.
00101->third.
01110->initial.
10111->first clk pulse.
01011->second.
00101->third.
(2)
Prakash said:
1 decade ago
Couldn't understand. Please will you elaborate it.
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