Digital Electronics - Number Systems and Codes - Discussion
Discussion Forum : Number Systems and Codes - General Questions (Q.No. 6)
6.
Decode the following ASCII message.
10100111010100101010110001001011001
01000001001000100000110100101000100
Discussion:
47 comments Page 4 of 5.
Sundar said:
1 decade ago
@Vinsian
Excellent explanation. Thanks.
Excellent explanation. Thanks.
Anuradha said:
1 decade ago
Good explanation!
Mashewsar 9700959156 said:
1 decade ago
ASCII value for
A = 65, B = 66, ....
a = 98, b = 99, ....
A = 65, B = 66, ....
a = 98, b = 99, ....
Rani said:
1 decade ago
Why we have to Split Only to 7 bits?
Nagarajan said:
1 decade ago
Vinsan, Your explaination is good..
Pavithra said:
1 decade ago
I too doubt why we have to split only to 78 bits?
Sukriti said:
9 years ago
For ASCII
A = 65, B = 66, ............................, Z = 90.
a = 97, b = 98, ......................................., z = 122.
91 = [
92 = \
93 = ]
94 = ^
95 = _
96 = ` (above Tab key known as Back quote)
A = 65, B = 66, ............................, Z = 90.
a = 97, b = 98, ......................................., z = 122.
91 = [
92 = \
93 = ]
94 = ^
95 = _
96 = ` (above Tab key known as Back quote)
RGN said:
1 decade ago
We need take only 7bits because 2^7=128 which maximum ASCII value instead of that if we consider 8bits then 2^8 corresponds to 256 which is not the range of ASCII value.
Inder said:
1 decade ago
ASCII is a 7-bit code
Vidhi said:
1 decade ago
We consider 8bits then 2^8.
But we have consider bits are signed bit that time only consider 2^8 bits.
But we have consider bits are signed bit that time only consider 2^8 bits.
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