Digital Electronics - Number Systems and Codes - Discussion

Discussion Forum : Number Systems and Codes - General Questions (Q.No. 6)
6.
Decode the following ASCII message.
10100111010100101010110001001011001
01000001001000100000110100101000100
STUDYHARD
STUDY HARD
stydyhard
study hard
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
47 comments Page 3 of 5.

Bhojan Shiwa said:   6 years ago
WAVE=13
TAXI= 8
HALT=10
FAIL= ?
Please solutions.

Prasanna said:   5 years ago
Thanks @Vinsan.

Aditya Nandekar said:   5 years ago
I can't understand, give me an example.

Ram said:   1 month ago
Good explanation. Thanks all.

Madhu said:   1 decade ago
I doubt why only 7 bits?

Rams said:   1 decade ago
Please any one explain me, I cant understand these.

Sheenu said:   1 decade ago
010100111010100101010110001001011001
01000001001000100000110100101000100
Add 0 to LHS to make it a multiplier of 4
now... 0101 0011=53..that is the hexadecimal of 'S'
Likewise 54 of 'T'
55 of 'U'
.
.
.
20 of space
Hence solved..

Deepika said:   1 decade ago
I can't understand this explanation please explain.

Billa said:   1 decade ago
Hey @deepika it is simple yaar. Take left side eight digits.

Eg: 01010011 this represent 53. That is the hex dec 53.

Madhu said:   1 decade ago
Hey but according to ASCII table 53 means U, how come here they have taken S for 53 !?


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