Digital Electronics - Number Systems and Codes - Discussion

Discussion Forum : Number Systems and Codes - General Questions (Q.No. 6)
6.
Decode the following ASCII message.
10100111010100101010110001001011001
01000001001000100000110100101000100
STUDYHARD
STUDY HARD
stydyhard
study hard
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
47 comments Page 1 of 5.

Deepika said:   1 decade ago
How to decode the ASCII msg?

Rams said:   1 decade ago
Please any one explain me, I cant understand these.

Sheenu said:   1 decade ago
010100111010100101010110001001011001
01000001001000100000110100101000100
Add 0 to LHS to make it a multiplier of 4
now... 0101 0011=53..that is the hexadecimal of 'S'
Likewise 54 of 'T'
55 of 'U'
.
.
.
20 of space
Hence solved..

Deepika said:   1 decade ago
I can't understand this explanation please explain.

Billa said:   1 decade ago
Hey @deepika it is simple yaar. Take left side eight digits.

Eg: 01010011 this represent 53. That is the hex dec 53.

Madhu said:   1 decade ago
Hey but according to ASCII table 53 means U, how come here they have taken S for 53 !?

Vinsan said:   1 decade ago
Correct Explanation available here:

Step 1: Divide the code into 7-bits each

(1010011) (1010100) (1010101) (1000100) (1011001)
(0100000) (1001000) (1000001) (1010010) (1000100)

Step 2: Convert binary data to decimal individually

Step 3: (83) (84) (85) (68) (89) (32) (72) (65) (82) (68)

Step 4: Substitute characters of ASCII values

Example:-
65-A
66-B
67-C
....
....
90-Z
32-blank, etc.

i.e code converted into text as STUDY HARD

Note:- If given data is not consisting 7 multiples of bits then append 0's to MSB i.e left hand side of data.

Also you should remember that characters case i.e upper or lower.
(4)

Sundar said:   1 decade ago
@Vinsian

Excellent explanation. Thanks.

Anuradha said:   1 decade ago
Good explanation!

Mashewsar 9700959156 said:   1 decade ago
ASCII value for

A = 65, B = 66, ....

a = 98, b = 99, ....


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