Digital Electronics - Memory and Storage - Discussion
Discussion Forum : Memory and Storage - General Questions (Q.No. 75)
75.
How many 8 k × 1 RAMs are required to achieve a memory with a word capacity of 8 k and a word length of eight bits?
Discussion:
2 comments Page 1 of 1.
Jupally chandra said:
1 decade ago
How do we need eight. Can anyone explain me?
Toshu said:
9 years ago
Yes, sure.
Here 8k x 1 means (8 * 1024 * 1) ok, here 1 is the word length means 1 bit, now we have to generate 8k * 8 size of memory, so just divide it as given.
Number of RAMs needed = (8k * 8)/(8k * 1) = 8.
Ans = 8.
Here 8k x 1 means (8 * 1024 * 1) ok, here 1 is the word length means 1 bit, now we have to generate 8k * 8 size of memory, so just divide it as given.
Number of RAMs needed = (8k * 8)/(8k * 1) = 8.
Ans = 8.
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