Digital Electronics - Memory and Storage - Discussion
Discussion Forum : Memory and Storage - General Questions (Q.No. 45)
45.
How many address lines would be required for a 2K × 4 memory chip?
Discussion:
4 comments Page 1 of 1.
Adarsh said:
7 years ago
It means that a memory of 2048 words, where each word is 4 bits.
So, to address 2048 (or 2K, where K means 2^10 or 1024), you need 11 bits, So 11 address lines.
So, to address 2048 (or 2K, where K means 2^10 or 1024), you need 11 bits, So 11 address lines.
Ajaj Ahmad said:
8 years ago
1k=2^10,
Then 2k =2^1 *2^10,
= 2^11 so option c is right.
Then 2k =2^1 *2^10,
= 2^11 so option c is right.
DHARMA MOHAN said:
9 years ago
2^p - M.
2^11 - 2 * 1024.
2048 - 2048.
2^11 - 2 * 1024.
2048 - 2048.
Pavani said:
1 decade ago
2K = 2 * 1K = 2^1 * 2^10 = 2^11
11 address lines are needed
11 address lines are needed
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers