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Digital Electronics - Memory and Storage - Discussion

Discussion Forum : Memory and Storage - General Questions (Q.No. 16)
Memory and Storage
16.

For the given circuit, which of the following is correct?

The number 5 is being written to the memory at address location 203.
The chip has not been enabled, since the EN terminal is 0; therefore, nothing will be written to the chip and the output is tri-stated.
Decimal 10 is being written into memory location 211.
The read/write line is LOW; therefore, decimal 5 is being stored at memory location 211.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
4 comments Page 1 of 1.
Unknown said:   1 decade ago
As the CS is active low when 0 is given as input it is activated, for read and write the input is 0.

So as write is active low it is activated and the data given is 1010(b) = 10(d) and is written onto memory as 1101001(b) = 211(d).
Garv said:   1 decade ago
EN is at active low means it is active when 0 is given to it. So it can't be write answer.
Abhishek said:   1 decade ago
But if assuming that the en is activated stil number 5 is written at 203 location!
Santiago said:   1 decade ago
The answer is C. It's an active LOW. The input is 0 - Therefore it's activated.
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