Digital Electronics - Digital Concepts - Discussion

Discussion Forum : Digital Concepts - General Questions (Q.No. 5)
5.
The range of voltages between VL(max) and VH(min) are ________.
unknown
unnecessary
unacceptable
between 2 V and 5 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
38 comments Page 2 of 4.

BHARGAV said:   1 decade ago
I think that the values are not necessary as the circuit operates for either max or min with acceptable errors.

ARIF said:   1 decade ago
It is unacceptable because of emitter current is zero.

Parul said:   1 decade ago
My question is if value vary from manufacture then its value should be unknown, why it is not acceptable? If in any IC value matches then what?

Rudrasen pal said:   1 decade ago
I think in digital by quantization.

We make that level of supply according to our device.

Generally its 0/5 volt.

Shrenika said:   1 decade ago
Why it is unacceptable?

Pooja said:   1 decade ago
There is something called strong 0 and weak 1. Could that be related here, because a voltage near to 5V say 4.8V is treated as strong 1.

Sai krishna kasam said:   1 decade ago
It won't make sense if set max and min voltages without knowing circuit components so acceptable.

Rahul said:   1 decade ago
Generally In digital logic design there are voltage and current parameters defined so regarding to these parameters it is described that the voltage range between the Vlmax and VHmin in unacceptable i.e it is neither 1 nor 0.

Mohit pathak said:   1 decade ago
Normally looking at the options. Option A is not ok because voltages are known and can be measured. Option B Is not ok because all measurable quantity has it's significance. Option D cannot be because we observe less than 2 volt while measuring and 1.5 we do work as low limit. So, would like to go for Option C, because we always go for 0 and 1 in digital electronics so min and max limit are unacceptable.

Regine said:   1 decade ago
How many voltage that can take in?


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