Digital Electronics - Digital Concepts - Discussion

Discussion Forum : Digital Concepts - General Questions (Q.No. 5)
5.
The range of voltages between VL(max) and VH(min) are ________.
unknown
unnecessary
unacceptable
between 2 V and 5 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
38 comments Page 1 of 4.

Mohit pathak said:   1 decade ago
Normally looking at the options. Option A is not ok because voltages are known and can be measured. Option B Is not ok because all measurable quantity has it's significance. Option D cannot be because we observe less than 2 volt while measuring and 1.5 we do work as low limit. So, would like to go for Option C, because we always go for 0 and 1 in digital electronics so min and max limit are unacceptable.

Anubhav said:   4 years ago
In this world of semiconductor, anything above VL (max) and below VH (min) is unacceptable, because that is called state of uncertainty.

It has to do with noise margins and fabrication defects. VL (max) is acceptable noise margin for low state, VH (min) is acceptable noise margin for high state.

Actual voltages may differ from implementations to designs and fabrication methods.
(2)

Gaurav said:   1 decade ago
Digital devices works on 0 and 1 only. i.e. for 0, the voltage range is VLmin-VLmax and for 1, its VHmin-VHmax. So, the gap between VLmax and VHmin means nothing to a digital system because its neither 0 nor 1. Its just a transition state.

That's why, this region is unacceptable for digital devices.

This question is from digital point of view, not from analog.

Jigar said:   1 decade ago
It is unacceptable in some sense like the components are made by various manufacturers so if we fixed minnimum Vl then the component made by one manufactrer may work on tht voltage but on the same voltage, component made by another manufactere may not work on tht voltage. So my mean to say is the voltage values may varies depending on manufacterers datasheet.

Kiran said:   9 years ago
Digital circuits are mainly for "low power applications".

So, as Jigar said manufacturer have a requirement to make an IC in which 1-means a high voltage level (Vdd) similarly 0 for low voltage (some. X). That Vdd and x depends on requirement and transistor technology in which IC is manufacturing (channel length).

So the answer is C.

Prashanth said:   5 years ago
It's not about real voltages. In an ideal world, Digital circuits will have one single high voltage for 1 and another single low voltage for 0. All others are not allowed. Two voltage levels for two symbols. However this is not possible due to noise and hence we consider small ranges for both. So, ideally option C is correct.

Murugan said:   1 decade ago
@Kishore is right answer, in digital electronics logic 0 and logic 1 are the two states, there is none others. Some students said 1.5 is treated as 0 and 3.5 is treated as 1, but even though the voltage is 3.5, then why you are taken it as 1 or 5v because it is unacceptable in digital electronics.

Rahul said:   1 decade ago
Generally In digital logic design there are voltage and current parameters defined so regarding to these parameters it is described that the voltage range between the Vlmax and VHmin in unacceptable i.e it is neither 1 nor 0.

S.prem kumar said:   1 decade ago
As karthik said, vl and vh values vary from manufacturer to manufacturer. Because, one manufacturer may design for one volategs but on that same voltages, no other manufacturer component doesn't work. So, it is unacceptable.

Kishore said:   1 decade ago
The range of voltages between VL(max) and VH(min) are unacceptable because in digital system VL(max) is taken as 1 and VH(min) is taken as 0. Other valtages in between are not accepted in the digital system.


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