Digital Electronics - Counters - Discussion
Discussion Forum : Counters - Filling the Blanks (Q.No. 20)
20.
A 4-bit binary up counter has an input clock frequency of 20 kHz. The frequency of the most significant bit is ________.
Discussion:
4 comments Page 1 of 1.
KIRAN V said:
5 years ago
As it is a 4 bit up counter, requires 4 Flip Flops.
Each Flip Flop divides the input frequency by 2. ie. f/2, f/4, f/8, f/16.
So Output frequency = input frequency/16,
Output frequency = 20 KHz/16,
Output frequency = 1.25 KHz.
Each Flip Flop divides the input frequency by 2. ie. f/2, f/4, f/8, f/16.
So Output frequency = input frequency/16,
Output frequency = 20 KHz/16,
Output frequency = 1.25 KHz.
Hiren said:
1 decade ago
If I am not wrong,
We need to take input clock is = 20k/2.
So count on basis of 10k clock.
And MSB changes on 8th stage so = 10k/8 = 1.25k answer.
We need to take input clock is = 20k/2.
So count on basis of 10k clock.
And MSB changes on 8th stage so = 10k/8 = 1.25k answer.
Anonymous said:
7 years ago
As it is a 4 bit up counter, it has 16 States in total ie. From 0000 to 1111.
And it's i/p clock is given as 20.
So 20÷16 = 1.25khz.
And it's i/p clock is given as 20.
So 20÷16 = 1.25khz.
JAYA said:
7 years ago
We need to take input clock is = 20k/2.
What it means? Can anyone explain? please
What it means? Can anyone explain? please
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