Digital Electronics - Counters - Discussion

Divide by 16 and get the remainder as the lsb of the hexadecimal, repeat the process till the complete of all division.

Explanation:

1) 15536/16 = rem(0) & quo(971). The lsb of hexadecimal is 0.
2) 971/16 = rem(11) & quo(60). The next to lsb is 11, i.e., B.
3) 60/16 = rem(12) & quo(3). The second next to lsb is 12, i.e., C.
4) 3/16 = rem(3) & quo(0). The last one is 3.

So the final answer be (3CB0).

You just division the number by 2 at the end and use LSB to MSB when write in sequence. And make the pair of four bit from right to left. The answer will be came.

First take the binary numbers like:

15,536 = 2^13+2^12+2^11+2^10+2^7+2^5+2^4.

= 0011 1100 1011 0000 = 3CB0.

@Amarjeet.

Thanks for giving an explanation.

You are right. Thanks @Amarjeet.

Thank you for the explanation.

How the calculation is done?

How did you take binary?