Digital Electronics - Counters - Discussion

Divide by 16 and get the remainder as the lsb of the hexadecimal, repeat the process till the complete of all division.

Explanation:

1) 15536/16 = rem(0) & quo(971). The lsb of hexadecimal is 0.
2) 971/16 = rem(11) & quo(60). The next to lsb is 11, i.e., B.
3) 60/16 = rem(12) & quo(3). The second next to lsb is 12, i.e., C.
4) 3/16 = rem(3) & quo(0). The last one is 3.

So the final answer be (3CB0).

First take the binary numbers like:

15,536 = 2^13+2^12+2^11+2^10+2^7+2^5+2^4.

= 0011 1100 1011 0000 = 3CB0.

How did you take binary?

How the calculation is done?

You just division the number by 2 at the end and use LSB to MSB when write in sequence. And make the pair of four bit from right to left. The answer will be came.

@Amarjeet.

Thanks for giving an explanation.

You are right. Thanks @Amarjeet.

Thank you for the explanation.