Digital Electronics - Counters - Discussion
Discussion Forum : Counters - General Questions (Q.No. 34)
34.
Three cascaded modulus-5 counters have an overall modulus of ________.
Discussion:
7 comments Page 1 of 1.
Pooja said:
7 years ago
How? Explain.
(1)
Raghavendra said:
1 decade ago
Cube of 5 = 125.
Vijaya said:
7 years ago
5 * 5 * 5 = 125.
Bablu kushawaha said:
7 years ago
Not understanding this. Plese explain.
Muleya said:
7 years ago
5 * 5 * 5 = 125.
Muleya Junior said:
7 years ago
Each counter is cascaded with mod 5. And there are 3 cascaded counters which means the product of three mod 5 Cascaded counters is 25.
Shristi said:
5 years ago
Simply each cascaded state consider f/mod for frequency division.
And the next stage takes f as previously divided frequency.
Ex-100/5=20 (stage1) ,
20/5=4 (stage2) ,
4/5=0. 8 (stage3) or 100/125=0.8 here 125 is 5*5*5.
And the next stage takes f as previously divided frequency.
Ex-100/5=20 (stage1) ,
20/5=4 (stage2) ,
4/5=0. 8 (stage3) or 100/125=0.8 here 125 is 5*5*5.
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