Digital Electronics - Counters - Discussion
Discussion Forum : Counters - General Questions (Q.No. 3)
3.
A MOD-16 ripple counter is holding the count 10012. What will the count be after 31 clock pulses?
Discussion:
18 comments Page 2 of 2.
Shubham said:
10 years ago
Yeah bro you're right here its not specified its up or down counter but I thought if its not given what type of its we assume up counter.
Prashanth said:
10 years ago
There are two options 1000 and 1010 how to say it? whether a up counter or a down counter? If it is up it will be 1010 if it is down 1000. Am I right?
Shashank said:
1 decade ago
Since its a MOD-16 counter the current state that is 1001 will repeat at the 16th pulse. So 1001 will come on the application of 32nd clock pulse. We need the output at 31st pulse which is one less than 1001(9) which is 1000(8).
(1)
Mikki said:
1 decade ago
The question says after 31, so the next is 32.
Viju said:
1 decade ago
Give me a complete Explanation?
Seema said:
1 decade ago
How? find the clock pulse? for 32?
Swathi said:
1 decade ago
Current state of flip-flop is 9(1001), means total 9 pulses are completed and we require after 31 pulses, So total clock pulses are 40.
MOD-16 ripple counter count 16 states and it will repeat again. so for 2nd round 32 clock pulses are completed.
Therefore 40-32 = 8.
MOD-16 ripple counter count 16 states and it will repeat again. so for 2nd round 32 clock pulses are completed.
Therefore 40-32 = 8.
Brahma Rao K V said:
1 decade ago
Mod-16 means the output will repeats for 16th pulse again 32th pulse ok here present the data is 1001=9.
So for 31th pulse it is (1001)-(0001) = 1000 = 8.
So for 31th pulse it is (1001)-(0001) = 1000 = 8.
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