Digital Electronics - Counters - Discussion
Discussion Forum : Counters - General Questions (Q.No. 3)
3.
A MOD-16 ripple counter is holding the count 10012. What will the count be after 31 clock pulses?
Discussion:
18 comments Page 1 of 2.
Madhvi Sukhanandi said:
6 years ago
It holds 1001state, that why it's complete 16 clk and after it's starting initial 0000 state and then again start another 16 clk so 16+16=32.
so after another 16 clk also state is 1001, so 32 clk state is 1001=9 and 31 clk is 1000 =8 state. Because
0000=0 it's clk is 0.
0001=1 it's clk is 1.
.
.
0111=7 it's clk is 30,
1000=8 it's clk is 31,
1001=9 it's clk is 32.
so after another 16 clk also state is 1001, so 32 clk state is 1001=9 and 31 clk is 1000 =8 state. Because
0000=0 it's clk is 0.
0001=1 it's clk is 1.
.
.
0111=7 it's clk is 30,
1000=8 it's clk is 31,
1001=9 it's clk is 32.
(9)
Vivek said:
8 years ago
@Rakib Hasan.
The Mod-10 counter has 10 states and will repeat its initial state(state at clock 0) after every 10 clock pulses(i.e. whenever the clock is multiple of 10 e.g. 10, 20, 30, 40,.............200 etc).
Here initial state is 1010,
After 10 clock state is 1010.
After 20 clock state is 1010.
So on;
After 200 clock state is 1010.
The Mod-10 counter has 10 states and will repeat its initial state(state at clock 0) after every 10 clock pulses(i.e. whenever the clock is multiple of 10 e.g. 10, 20, 30, 40,.............200 etc).
Here initial state is 1010,
After 10 clock state is 1010.
After 20 clock state is 1010.
So on;
After 200 clock state is 1010.
Swathi said:
1 decade ago
Current state of flip-flop is 9(1001), means total 9 pulses are completed and we require after 31 pulses, So total clock pulses are 40.
MOD-16 ripple counter count 16 states and it will repeat again. so for 2nd round 32 clock pulses are completed.
Therefore 40-32 = 8.
MOD-16 ripple counter count 16 states and it will repeat again. so for 2nd round 32 clock pulses are completed.
Therefore 40-32 = 8.
RISHI NIGAM said:
4 years ago
As the counter is 16 base so it repeats after 16 clock pulse now we have to find after 31 we know after 32 which is multiple of 16.
So, at 31 it will be the same to 15 because after 32 it will repeat as counter is modulus counter.
So, at 31 it will be the same to 15 because after 32 it will repeat as counter is modulus counter.
(2)
Shashank said:
1 decade ago
Since its a MOD-16 counter the current state that is 1001 will repeat at the 16th pulse. So 1001 will come on the application of 32nd clock pulse. We need the output at 31st pulse which is one less than 1001(9) which is 1000(8).
(1)
Shivam Kumar Jha said:
2 years ago
If we start from 0000 then after 16 clock pulses we again reach 0000.
Therefore at the 15th clock pulse, we are one short of the count, we started with.
So, the answer would be 1000.
Therefore at the 15th clock pulse, we are one short of the count, we started with.
So, the answer would be 1000.
Rakib Hasan said:
8 years ago
Assume that the MOD-10 counter is in the 1010 state. What will be the state (count) after 200.
Pulses have been applied.
*If anyone knows this answer please explain me.
Pulses have been applied.
*If anyone knows this answer please explain me.
(1)
Brahma Rao K V said:
1 decade ago
Mod-16 means the output will repeats for 16th pulse again 32th pulse ok here present the data is 1001=9.
So for 31th pulse it is (1001)-(0001) = 1000 = 8.
So for 31th pulse it is (1001)-(0001) = 1000 = 8.
Prashanth said:
10 years ago
There are two options 1000 and 1010 how to say it? whether a up counter or a down counter? If it is up it will be 1010 if it is down 1000. Am I right?
Shubham said:
10 years ago
Yeah bro you're right here its not specified its up or down counter but I thought if its not given what type of its we assume up counter.
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