Digital Electronics - Counters - Discussion
Discussion Forum : Counters - General Questions (Q.No. 3)
3.
A MOD-16 ripple counter is holding the count 10012. What will the count be after 31 clock pulses?
Discussion:
18 comments Page 1 of 2.
Madhvi Sukhanandi said:
6 years ago
It holds 1001state, that why it's complete 16 clk and after it's starting initial 0000 state and then again start another 16 clk so 16+16=32.
so after another 16 clk also state is 1001, so 32 clk state is 1001=9 and 31 clk is 1000 =8 state. Because
0000=0 it's clk is 0.
0001=1 it's clk is 1.
.
.
0111=7 it's clk is 30,
1000=8 it's clk is 31,
1001=9 it's clk is 32.
so after another 16 clk also state is 1001, so 32 clk state is 1001=9 and 31 clk is 1000 =8 state. Because
0000=0 it's clk is 0.
0001=1 it's clk is 1.
.
.
0111=7 it's clk is 30,
1000=8 it's clk is 31,
1001=9 it's clk is 32.
(9)
Jakir said:
4 years ago
Consider a Mod - 32 counter.
What will be the count after 65 pulses? Anyone, please explain this.
What will be the count after 65 pulses? Anyone, please explain this.
(3)
RISHI NIGAM said:
4 years ago
As the counter is 16 base so it repeats after 16 clock pulse now we have to find after 31 we know after 32 which is multiple of 16.
So, at 31 it will be the same to 15 because after 32 it will repeat as counter is modulus counter.
So, at 31 it will be the same to 15 because after 32 it will repeat as counter is modulus counter.
(2)
Ayyan said:
4 years ago
How to find the clock pulse will be 16?
(1)
Shashank said:
1 decade ago
Since its a MOD-16 counter the current state that is 1001 will repeat at the 16th pulse. So 1001 will come on the application of 32nd clock pulse. We need the output at 31st pulse which is one less than 1001(9) which is 1000(8).
(1)
Shubhranshu said:
7 years ago
Thanks all for explaining this.
(1)
Rakib Hasan said:
8 years ago
Assume that the MOD-10 counter is in the 1010 state. What will be the state (count) after 200.
Pulses have been applied.
*If anyone knows this answer please explain me.
Pulses have been applied.
*If anyone knows this answer please explain me.
(1)
Yaswant said:
8 years ago
1001 = 9.
After 31 means 9+31 = 40,
Ripple counter after 9=1000,
Then 0000,
Then 0001------------> 1000.
After 31 means 9+31 = 40,
Ripple counter after 9=1000,
Then 0000,
Then 0001------------> 1000.
Shivam Kumar Jha said:
2 years ago
If we start from 0000 then after 16 clock pulses we again reach 0000.
Therefore at the 15th clock pulse, we are one short of the count, we started with.
So, the answer would be 1000.
Therefore at the 15th clock pulse, we are one short of the count, we started with.
So, the answer would be 1000.
Vivek said:
8 years ago
@Rakib Hasan.
The Mod-10 counter has 10 states and will repeat its initial state(state at clock 0) after every 10 clock pulses(i.e. whenever the clock is multiple of 10 e.g. 10, 20, 30, 40,.............200 etc).
Here initial state is 1010,
After 10 clock state is 1010.
After 20 clock state is 1010.
So on;
After 200 clock state is 1010.
The Mod-10 counter has 10 states and will repeat its initial state(state at clock 0) after every 10 clock pulses(i.e. whenever the clock is multiple of 10 e.g. 10, 20, 30, 40,.............200 etc).
Here initial state is 1010,
After 10 clock state is 1010.
After 20 clock state is 1010.
So on;
After 200 clock state is 1010.
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