Digital Electronics - Counters - Discussion
Discussion Forum : Counters - General Questions (Q.No. 66)
66.
What is the maximum delay that can occur if four flip-flops are connected as a ripple counter and each flip-flop has propagation delays of tPHL = 22 ns and tPLH = 15 ns?
Discussion:
7 comments Page 1 of 1.
Ankit said:
1 decade ago
Please clarify that whether the ripple counter is synchronous or asynchronous.
Because when it is asynchronous then the total delay is 4*(tplh+tphl)/2 else it would be only (tplh+tphl)/2;
Because when it is asynchronous then the total delay is 4*(tplh+tphl)/2 else it would be only (tplh+tphl)/2;
Yisha said:
1 decade ago
Maximum propagation delay is the longest
delay between an input changing value and
the output changing value
hence 22 * 4 = 88
delay between an input changing value and
the output changing value
hence 22 * 4 = 88
Raghavendra said:
1 decade ago
We have to consider worst case transition that is "1111" to "0000" here, as tphl is greater. So 22*4 = 88 ns.
Yisha said:
1 decade ago
If asked the average prp. delay = (Tphl + Tplh) /2
Sunil said:
9 years ago
@Ankit.
It is asynchronous counter.
It is asynchronous counter.
Alen said:
8 years ago
Ripple counter is asynchronous.
Shivanand said:
1 decade ago
Thanks Yisha.
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