Digital Electronics - Counters - Discussion

The given ckt is 3-bit ripple counter.

This counter o/p takes from Q0, Q1 & Q2.
it counts from 000 to 111 all these 3 o/p Q0, Q1^ & Q2 are giving to AND gate it produces X o/p.
For AND gate if all input is high '1' then o/p is high Otherwise low '0';
For o/p X '1' means(here x is AND o/p).
for this ckt

Q0 Q1^ Q2
1 0 1
only at this state all i/p of AND connected to ligic1.
so X is high only at this state.
its decimal value is 5.
Answer is 5.

All i/p must be '1'.

Leave everything and just check the and gate. It has 3 inputs in the circuit right!

The output of and the gate will be true only if all of its inputs are 1.

Then, check all the 3 inputs to where those were connected.

1st input ----to positive output Q0.
2nd input-----to negative output Q1.
3rd input-------to positive output Q2.

We are taking 2nd input from the bubble i.e., negative that means the original output Q2 shoud be 0 to give 1 after complementing.

This gives the answer 101 5, 5.

No of flip flops are 3 because flip flop is a one-bit storage element. So, the answer is 5 (101).