Digital Electronics - Combinational Logic Circuits - Discussion
Discussion Forum : Combinational Logic Circuits - General Questions (Q.No. 27)
27.
A logic probe is placed on the output of a gate and the display indicator is dim. A pulser is used on each of the input terminals, but the output indication does not change. What is wrong?
Discussion:
6 comments Page 1 of 1.
Ashwin said:
4 years ago
Which apparatus we are using is show dim on a low level and 1 at a high level, so it is dim.
And now about the answer, it is not tristate because we also checked by giving a pulse on every input if it tristate then it had to be given at least one when we give input on the onoff terminal.
And now about the answer, it is not tristate because we also checked by giving a pulse on every input if it tristate then it had to be given at least one when we give input on the onoff terminal.
Anonymous said:
2 years ago
The display's dim state is maybe because it is in a low-power state. It is nowhere related to the hardware being jn tristate. Since terminals are open, hence no result in terms of brightness can be seen here.
Neeraja said:
4 years ago
If it is the open circuit then how can the blub glows dim ? I don't understand? please explain to me.
Rushi said:
9 years ago
Why the gate can't be tri-stated? please explain.
Ashwani dwivedi said:
8 years ago
Why not C? Explain please.
Mitesh Patel said:
9 years ago
Can anybody explain?
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