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Digital Electronics - Combinational Logic Circuits

Exercise : Combinational Logic Circuits - General Questions
26.
The binary numbers A = 1100 and B = 1001 are applied to the inputs of a comparator. What are the output levels?
A > B = 1, A < B = 0, A < B = 1
A > B = 0, A < B = 1, A = B = 0
A > B = 1, A < B = 0, A = B = 0
A > B = 0, A < B = 1, A = B = 1
Answer: Option
Explanation:
No answer description is available. Let's discuss.
27.
A logic probe is placed on the output of a gate and the display indicator is dim. A pulser is used on each of the input terminals, but the output indication does not change. What is wrong?
The output of the gate appears to be open.
The dim indication on the logic probe indicates that the supply voltage is probably low.
The dim indication is a result of a bad ground connection on the logic probe.
The gate may be a tristate device.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
28.
Two 4-bit binary numbers (1011 and 1111) are applied to a 4-bit parallel adder. The carry input is 1. What are the values for the sum and carry output?
4321 = 0111, Cout = 0
4321 = 1111, Cout = 1
4321 = 1011, Cout = 1
4321 = 1100, Cout = 1
Answer: Option
Explanation:
No answer description is available. Let's discuss.
29.
Each "1" entry in a K-map square represents:
a HIGH for each input truth table condition that produces a HIGH output.
a HIGH output on the truth table for all LOW input combinations.
a LOW output for all possible HIGH input conditions.
a DON'T CARE condition for all possible input truth table combinations.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
30.
Looping on a K-map always results in the elimination of:
variables within the loop that appear only in their complemented form.
variables that remain unchanged within the loop.
variables within the loop that appear in both complemented and uncomplemented form.
variables within the loop that appear only in their uncomplemented form.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
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